The key is a process called <span>pasteurization</span>
3. they make up larger compounds like fats and amino acids, would be the correct answer.
Answer:
I think we would need to see the animation.
Answer:
The heat required to melt 7.35 g of benzene at its normal melting point is 934.8 Joules.
The heat required to vaporize 7.35 g of benzene at its normal melting point is 2,893 Joules.
Explanation:
Mass of benzene = 7.35 g
Moles of benzene = 
Heat fusion of benzene,
1) Heat required to melt 7.35 g of benzene at its normal melting point = Q


(1 kJ = 1000 J)
2) Heat vaporization of benzene,
Heat required to vaporize 7.35 g of benzene at its normal melting point = Q


(1 kJ = 1000 J)