Answer:
a. 2954g of FeS
b. 1143g of FeS
Explanation:
Based on the reaction:
8 Fe + S₈ → 8 FeS
<em>8 moles of Fe reacts with 1 mole of S₈ to produce 8 moles of FeS</em>
<em />
a. 4.2mol sulfur produce:
4.2mol S₈ × ( 8 mol FeS / 1 mol S₈) = <em>33.6mol FeS</em>. As molar mass of FeS is 87.92g/mol, mass is:
33.6mol FeS × ( 87.92g / 1 mol FeS) = <em>2954g of FeS</em>
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b. 13mol Fe produce:
13mol Fe × ( 8 mol FeS / 8 mol Fe) = <em>13mol FeS</em>. In mass:
13 mol FeS × ( 87.92g / 1 mol FeS) = <em>1143g of FeS</em>
<h3>
Answer: 4.25 g/ml %</h3>
Explanation:
weight/volume percentage concentration = (mass in g ÷ volume) × 100
= (0.850 g ÷ 20 ml) × 100
= 4.25 g/ml %
∴ the weight/volume percentage concentration of the sucrose solution is 4.25 g/ml %.
It will be number 1.
NO loses oxygen ie its being reduced to N2
NH3 gains oxygen atom ie its being oxidised to H2O
Answer:
HgSO₄
Explanation:
% => g => moles => ratio => reduce => empirical ratio
%Hg = 67.6% => 67.6g/201g/mol = 0.34mol
%S = 10.8% => 10.8g/32g/mol = 0.34mol
%O = 21.6% => 21.6g/16g/mol = 1.35mol
Hg:S:O => 0.34:0.34:1.35
Reduce to whole number ratio by dividing by the smaller mole value...
Hg:S:O => 0.34/.34:0.34/.34:1.35/.34 => Empirical Ratio = 1:1:4
∴ Empirical Formula is HgSO₄
#4 and #5:
To find pH given concentration of H+ or H30+
pH = - log (H+ or H30+ M)
To find pH given concentration of OH-
Since you already found the pH for this (in #4), you subtract #4's answer from 14.
14 - (pH) = pOH
