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Lady_Fox [76]
3 years ago
14

A submicroscopic particle suspended in a solution has a volume 1.3um^3. What is this volume in liters?

Chemistry
2 answers:
k0ka [10]3 years ago
5 0
1000 liters = 1 m^3

and
1.3um^3 = 1.3x10^(-6)m^3

multiply both sides of the first equation by 1.3x10^(-6)
1.3x10^(-6) * 1000 liters = 1.3x10^(-6) * 1m^3
1.3x10^(-3) liters = 1.3x10^(-6) m^3
MariettaO [177]3 years ago
3 0

Answer: 1.3\times 10^{-15} L.

Explanation:

Volume of the gas is defined as the space occupied by a substance. It is expressed in units like cm^3, m^3 , L and ml.

All these units of volume are inter convertible.

We are given:

Volume of the gas = 1.3\mu m^3

Converting this unit of volume into 'L' by using conversion factor:

10^{18}\mu m^3=1m^3

1.3\mu m^3=\frac{1}{10^{18}}\times 1.3=1.3\times10^{-18}m^3

1m^3=1000L

Thus 1.3\times 10^{-18}m^3=\frac{1000}{1}\times 1.3\times 10^{-18}=1.3\times 10^{-15} L

Thus the volume in Liters would be 1.3\times 10^{-15} L.

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A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh
Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C =  -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C =  4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

7 0
3 years ago
Which of the following is the smallest volume?
jok3333 [9.3K]
The     (B) answer     (B)     is    (B)               (B)           (B)


6 0
3 years ago
Using the reaction below determine the amount of Sulfur proceduced in grams (this is a limiting reaction question) 2 H2S + SO2 -
marusya05 [52]

Answer:

<u>= 2.2 g pf S. produced</u>

Explanation:

Balanced Reaction equation:

2H_{2} S + SO_{2} →  3S + 2H_{2} O

1 mole of H2S - 34.1g

? moles - 3.2g

= 3.2/34.1 =<u> 0.09 moles of H2S</u>

Also,

1 mole of S02 - 64.07 g

? moles - 4.42g

= 4.42/64.07 <u>= 0.069 moles of SO2</u>

<u />

<em>Meaning SO2 is the limiting reagent</em>

Finally, 3 moles of S -  32g of sulphur

0.069 mole = ? g of Sulphur

= 0.069 x 32

<u>= 2.2 g pf S.</u>

7 0
3 years ago
An increase in temperature results in A) a decrease in the required activation energy while the reaction rate remains constant.
N76 [4]

Answer:

C) an increase in rate of reaction because reactant molecules collide with greater energy

Explanation:

Temperature is one of the factors that affect the rate of a reaction. The rate of a reaction increases with an increase in temperature and vice versa. When the temperature of a reaction increases, the kinetic energy of the reactant molecules increases causing them to react at a faster rate.

The reactant molecules respond to an increase in temperature by colliding at a faster rate due to an increased kinetic energy between the reactant molecules.

7 0
3 years ago
What are the parts of a water molecule
astra-53 [7]

Answer:

2 hydrogen, 1 oxygen

Explanation:

H2 O

6 0
3 years ago
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