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Lady_Fox [76]
3 years ago
14

A submicroscopic particle suspended in a solution has a volume 1.3um^3. What is this volume in liters?

Chemistry
2 answers:
k0ka [10]3 years ago
5 0
1000 liters = 1 m^3

and
1.3um^3 = 1.3x10^(-6)m^3

multiply both sides of the first equation by 1.3x10^(-6)
1.3x10^(-6) * 1000 liters = 1.3x10^(-6) * 1m^3
1.3x10^(-3) liters = 1.3x10^(-6) m^3
MariettaO [177]3 years ago
3 0

Answer: 1.3\times 10^{-15} L.

Explanation:

Volume of the gas is defined as the space occupied by a substance. It is expressed in units like cm^3, m^3 , L and ml.

All these units of volume are inter convertible.

We are given:

Volume of the gas = 1.3\mu m^3

Converting this unit of volume into 'L' by using conversion factor:

10^{18}\mu m^3=1m^3

1.3\mu m^3=\frac{1}{10^{18}}\times 1.3=1.3\times10^{-18}m^3

1m^3=1000L

Thus 1.3\times 10^{-18}m^3=\frac{1000}{1}\times 1.3\times 10^{-18}=1.3\times 10^{-15} L

Thus the volume in Liters would be 1.3\times 10^{-15} L.

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Taya2010 [7]

Answer:

nH2SO4 = 0,1 mol

Đặt nNaOH = a; nKOH = 3a (mol)

Quy đổi phản ứng thành: {X, H2SO4} + {NaOH, KOH} → Muối + H2O

Ta có: nH+ = nOH- → 2nX + 2nH2SO4 = nNaOH + nKOH

→ 2.0,1 + 2.0,1 = a + 3a → a = 0,1

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BTKL: mX + mH2SO4 + mNaOH + mKOH = m muối + mH2O

→ mX + 0,1.98 + 0,1.40 + 0,3.56 = 36,7 + 0,4.18 → mX = 13,3 gam

→ MX = 13,3/0,1 = 133

→ %mN = (14/133).100% ≈ 10,526%

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2 years ago
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maria [59]
That is True XD
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3 years ago
g The first step in the process is to calibrate the grating, so we know the grating spacing (the distance between the openings i
Trava [24]

Answer:

The grating spacing is  d = 1055nm

Explanation:

From the question we are told that

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