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Dahasolnce [82]
3 years ago
10

Please help me this is a hard problem

Mathematics
1 answer:
Levart [38]3 years ago
7 0

Step-by-step explanation:

- 3y + 10 = x...(1) \\ 10x + 7y =  - 38...(2) \\ from \: equations \: (1) \: and \: (2) \\ 10( - 3y + 10) + 7y =  - 38 \\  - 30y + 100 + 7y =  - 38 \\  - 23y =  - 38 - 100 \\  - 23y =  - 138 \\ y =  \frac{ - 138}{ - 23}  \\  \huge \red { \boxed{y = 6}} \\ substituting \: y = 6 \: in \: equation \: (1) \\ x =  - 3 \times 6 + 10 =  - 18 + 10 =  - 8 \\   \huge \red { \boxed{x =  - 8}} \\  \\  \:  \:  \huge \purple{ \boxed{(x, \:  \: y) = ( - 8, \:  \: 6)}}

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