Answer:
One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.
Step-by-step explanation:
Given:
Both the system can complete the job = 9 minutes
We need find the time required by each system to do the job.
Solution:
Let the time required by another watering system to complete the job be 'x' mins.
Now given:
One watering system needs about three times as long to complete a job as another watering system.
Time required by one watering system = 
Rate to complete the job by another watering system = 
Rate to complete the job by One watering system = 
Rate at which both can complete the job = 
So we can say that;
Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.
framing in equation form we get;

Now taking LCM to make the denominator common we get;

By Cross multiplication we get;

Dividing both side by 3 we get;

Time required by One watering system = 
Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.
It sounds like <em>R</em> is the region (in polar coordinates)
<em>R</em> = {(<em>r</em>, <em>θ</em>) : 2 ≤ <em>r</em> ≤ 3 and 0 ≤ <em>θ</em> ≤ <em>π</em>/2}
Then the integral is

Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
2000 × 15% = 300
300 × 5 = 1500
2000 - 1500 = 500 population after 5 years
1.3 pages first you take 15 * by 60 because 60 min. in one hour and then divide 1200 by 900 you get 1.3