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Bingel [31]
3 years ago
13

Jeff, a snowboarder who weighs 1000 N, is practicing on a trampoline for an upcoming competition. As Jeff bounces straight up of

f the trampoline, his speed is 6.26 m/sec. When he reaches the top of his bounce, his potential energy is approximately:
Physics
1 answer:
NISA [10]3 years ago
5 0

Answer:

Potential energy P_E = 2000 J

Explanation:

Given data

Weight of the person = 1000 N

Mass of the person = \frac{1000}{9.81} = 102 kg

Speed = 6.26 \frac{m}{s}

Kinetic energy is given by

E_K = \frac{1}{2} m v^{2}

Put the values in above formula we get

E_K = \frac{1}{2}(102) 6.26^{2}

E_K = 2000 J

When the person reach top point then at this point the velocity is zero & kinetic energy at top point is equals to the potential energy.

Therefore potential energy

P_E = 2000 J

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In what direction does the medium move relative to the direction of the wave? Explain.
Artyom0805 [142]

As we can see that the boy is moving his hand up and down while producing the wave in the string.

Here we can see that the source of disturbance or source of wave here in this example is the boy who is holding the string at one end.

So here the motion of the hand of boy is representing the motion of medium molecules in the medium always

So here the disturbance of wave is travelling in the string to the right direction while if we see the direction of medium molecules then it is moving perpendicular to the string i.e. up and down

This type of wave is known as transverse waves in which medium molecules moves perpendicular to the direction of wave

8 0
3 years ago
A 50g ball is released from rest 1.0 above the bottom of thetrack
ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

The equation is

y=\dfrac{1}{4}x^2

We need to calculate the velocity

Using conservation of energy

\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

\Delta U_{i}=\Delta K_{f}

Put the value into the formula

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2

v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}

v=\sqrt{19.6}

v=4.42\ m/s

We need to calculate the maximum height of the ball

Using again conservation of energy

\dfrac{1}{2}mv^2=mgh

Here, h = y highest point

Put the value into the formula

\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h

y=\dfrac{0.5\times(4.42)^2}{9.8}

y=0.996\ m

Put the value of y in the given equation

y=\dfrac{1}{4}x^2

x^2=4\times0.996

x=\sqrt{4\times0.996}

x=1.99\ m\ \approx 2 m

Hence, The maximum height of the ball is 2 m.

4 0
3 years ago
Que volumen ocupan 0.4kg de alcohol, cual es el peso de este volumen
Ugo [173]

Answer: I don't know spanish

Explanation:

8 0
3 years ago
A substance a
Brums [2.3K]

Answer:

B. Medium

Explanation:

I don't know how to explain it but I already did this lesson in school

5 0
3 years ago
a person throws a ball in such a way that its speed is zero at one particular point in its path. How did the person throw the ba
Keith_Richards [23]

vertical! or in other words, up!


6 0
4 years ago
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