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Phoenix [80]
3 years ago
10

A developmental psychologist would be interested in studying __________. A. different philosophies about life after death B. psy

chological changes that occur during adolescence C. different countries that fought during World War II D. how literature patterns change over centuries
Physics
2 answers:
Sholpan [36]3 years ago
8 0
B nothing else has to do with developmental psych
Minchanka [31]3 years ago
3 0

Answer:

B.

psychological changes that occur during adolescence

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A container contains 200g of water at initial temperature of 30°C. An iron nail of mass 200g at temperature of 50°C is immersed
d1i1m1o1n [39]

Answer:

Assuming there is no heat loss to the surrounding.

Heat lost by iron equals heat gained by water.

0.2(450)(50-x)=0.2(4200)(x-30)

x=31.94 °C

Explanation:

4 0
3 years ago
Read 2 more answers
The mass of a hot-air balloon and its cargo (not including the air inside) is 170 kg. The air outside is at 10.0°C and 101 kPa.
scoundrel [369]

Answer:

108.37°C

Explanation:

P₁ = Initial pressure = 101 kPa

V₁ = Initial volume = 530 m³

T₁ = Initial temperature = 10°C = 10+273.15 =283.15 K

P₂ = Final pressure = 101 kPa (because it is open to atmosphere)

V₂ = Final volume = 530 m³

P₁V₁ = n₁RT₁

⇒101×530 = n₁RT₁

⇒53530 J = n₁RT₁

P₂V₂ = n₂RT₂

⇒53530 J = n₂RT₂

\frac{m_1}{m_2}=\frac{\rho V_1}{\rho V_1-170}\\\Rightarrow \frac{m_1}{m_2}=\frac{1.244\times 530}{1.244\times 530-170}=1.347\\\Rightarrow \frac{m_1}{m_2}=1.347\\\Rightarrow \frac{n_1}{n_2}=1.347

Dividing the first two equations we get

1=\frac{n_1}{n_2}\frac{T_1}{T_2}\\\Rightarrow 1=1.347\frac{283.15}{T_2}\\\Rightarrow T_2=1.347\times 283.15= 381.52\ K

∴Temperature must the air in the balloon be warmed before the balloon will lift off is 381.25-273.15 = 108.37°C

8 0
3 years ago
Why don't we feel pressure exerted by atmosphere?
ozzi
Crushing pressure. Human bodies are used to air pressure. The air pressure in our lungs, ears and stomachs is the same as the air pressure outside of our bodies, which ensures that we don't get crushed. Our bodies are also flexible enough to cope when the internal and external pressures aren't exactly the same.
6 0
3 years ago
The coefficient of linear expansion of steel is 12 × 10-6 K-1 . What is the change in length of a 25-m steel bridge span when it
Westkost [7]

Answer:

0.012-m

Explanation:

∆L = α × Lo × (T-To)

α is the coefficient of linear expansion = 12 × 10-6 K-1

Lo = Initial length = 25-m

∆L = Change in length

(T-To) = 40 K

∆L = 12 × 10-6 × 25 × 40

∆L = 0.012-m

4 0
3 years ago
A 2.5 kg , 20-cm-diameter turntable rotates at 150 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turnt
emmainna [20.7K]

The concepts required to solve this problem are those related to the conservation of the angular momentum and the moment of inertia of the disk. We will begin by calculating the moment of inertia of the disc, then the moment of inertia of the disc after the two two blocks hits and sticks to the edges of the turn table. In the end we will apply the conservation theorem.

The radius is given as,

R = \frac{20cm}{2} = 10cm = 0.1m

When a block falls from above and sticks to the turn table, the moment inertia of the turntable increases.

Since two blocks are stick to the turn table, the total final moment of inertia of the turntable is the sum moment of inertias of individual turntable, and two blocks.

I_1 = \frac{1}{2} MR^2

I_1 = \frac{1}{2} (2.5)(0.1)^2

I_1 = 0.0125kg \cdot m^2

The moment of inertia of each block is

I_0 = mR^2

Total moment of inertia of two block is

I_0' = 2mR^2

The final moment of inertia of the turn table is

I_2 = I_1 +I'0

I_2 = I_1 +2mR^2

I_2 = 0.01kg\cdot m^2 + 2(500*10^{-3}kg)(0.1m)^2

I_2 = 0.0225kg\cdot m^2

From the conservation of the angular momentum, the initial angular momentum of the system is equal to final angular momentum of the system,

Rearrange the equation we have that

I_1\omega_2 = I_2\omega_2

\omega_2 = \frac{I_1\omega_2}{I_2}

\omega_2 = \frac{0.01*150rpm}{0.0225}

\omega_2 = 66.67rpm

The magnitude of the turntable's angular velocity is 66.67rpm

3 0
3 years ago
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