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3 years ago

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A developmental psychologist would be interested in studying __________. A. different philosophies about life after death B. psy

chological changes that occur during adolescence C. different countries that fought during World War II D. how literature patterns change over centuries

2 answers:

Sholpan [36]3 years ago

8 0

B nothing else has to do with developmental psych

Minchanka [31]3 years ago

3 0

Answer:

B.

psychological changes that occur during adolescence

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A small first-aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of t

Artyom0805 [142]

Answer:

D = 30.625 m

Explanation:

given,

Speed of the climber = 1.3 m/s

time = 2.5 s

acceleration due to gravity = 9.8 m/s²

initial speed of the kit = 1.3 m/s

velocity of the kit after 2.5 s

using equation of motion

v = u + a t

v = 1.3 + 9.8 x 2.5

v = 25.8 m/s

distance travel by the kit in 2.5 s

v² = u² + 2 g h

25.8² = 1.3² + 2 x 9.8 x h

19.6 h = 663.95

h = 33.875 m

distance travel by the rock climber in 2.5 s

distance = speed of climber x time

h' = 1.3 x 2.5

h' = 3.25 m

Distance between kit and rock climber

D = h - h'

D = 33.875 - 3.25

D = 30.625 m

The kit is 30.625 m below climber.

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3 years ago

If water is split to form hydrogen and oxygen - is this a change of state and wht

xxTIMURxx [149]

It is a chemical change

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3 years ago

A thermometer is placed in water in order to measure the water’s temperature. What would cause the liquid in the thermometer to

yKpoI14uk [10]

It would be D. The kinetic energy would rise.

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4 years ago

A ray of light strikes a sheet of glass (n=1.5) at an angle of 25° with the normal. Find the angle of the refracted ray within t

IRINA_888 [86]

Answer:

(d) 16°

Explanation:

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 25.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (glass, n=1.5)

${n_i}$ is the refractive index of the incidence medium (air, n=1)

Hence,

$1\times {sin25.0^0}={1.5}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.2817$ = 16°

7 0

3 years ago

A circular copper wire is put in tension under a weight of 7000N. What is the ratio of its diameter after and before the load is

zaharov [31]

Answer:

$\frac{d_f}{d} =0.9999983$

Explanation:

Given:

force applied on the copper wire, $F=7000\ N$

cross sectional area of the wire, $a=0.01\ m^2$

Poisson's ratio, $\mu=0.3$

we have, Young's modulus, $E=128\times 10^3\ MPa$

<u>Stress induced due to the applied force:</u>

$\sigma=\frac{F}{a}$

$\sigma=\frac{7000}{0.01}$

$\sigma=700000\ Pa=0.7\ MPa$

<u>Now the longitudinal strain:</u>

<u /> $\epsilon=\frac{\sigma}{E}$ <u />

<u /> $\epsilon=\frac{0.7}{128\times 10^3}$ <u />

<u /> $\epsilon=5.468\times 10^{-6}$ <u />

Now from the relation of Poisson's ratio:

$\mu=\frac{\nu}{\epsilon}$

where:

$\nu=$ lateral strain

$0.3=\frac{\nu}{5.468\times 10^{-6}}$

$\nu=1.6406\times 10^{-6}$ ..................(1)

<u>Now we find the diameter of the wire:</u>

$a=\pi.\frac{d^2}{4}$

$0.01=\pi\times \frac{d^2}{4}$

$\frac{0.04}{\pi} =d^2$

$d=0.1128\ m=112.8\ mm$

<u>When the tensile load is applied its diameter decreases:</u>

The lateral strain is also given as,

$\nu=\frac{\Delta d}{d}$

$1.6406\times 10^{-6}=\frac{\Delta d}{112.8}$

$\Delta d=0.000185\ mm$

Now the final diameter will be:

$d_f=d-\Delta d$

$d_f=112.8-0.000185$

$d_f=112.799815\ mm$

Now the ratio:

$\frac{d_f}{d} =\frac{112.799815}{112.8}$

$\frac{d_f}{d} =0.9999983$

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3 years ago