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melomori [17]
3 years ago
6

Hey, what is antimatter

Physics
2 answers:
Vsevolod [243]3 years ago
6 0

Answer:

Antimatter is

molecules formed by atoms consisting of antiprotons, antineutrons, and positrons. Stable antimatter does not appear to exist in our universe.

jenyasd209 [6]3 years ago
5 0
A antimatter is particle physics, antimatter is a material composed of the antiparticle "partners" to the corresponding particles of ordinary matter. A particle and its antiparticle have the same mass as one another, but opposite electric charge and other quantum numbers.
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n a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kinetic
Annette [7]

Answer:

Explanation:

a ) starting from rest , so u = o and initial kinetic energy = 0 .

Let mass of the skier = m

Kinetic energy gained = potential energy lost

= mgh = mg l sinθ

= m x 9.8 x 70 x sin 30

= 343 m

Total kinetic energy at the base = 343 m  + 0 = 343 m .

b )

In this case initial kinetic energy = 1/2 m v²

= .5 x m x 2.5²

= 3.125 m

Total kinetic energy at the base

= 3.125 m  + 343 m

= 346.125 m

c ) It is not surprising as energy gained due to gravitational force by the earth is enormous . So component of energy gained due to gravitational force far exceeds the initial kinetic energy . Still in a competitive event , the fractional initial kinetic energy may be the deciding factor .

7 0
3 years ago
When an object is turning a corner what direction is the acceleration?
polet [3.4K]
If the corner is rounded and is perfectly circular, then the acceleration is centripetal and is always directed toward the center.
7 0
3 years ago
Calculate the de Broglie wavelength of an electron accelerated from rest through a potential difference of (a) 100 V, (b) 1.0 kV
forsale [732]

Answer:

(a) \lambda=1.227\ A

(b) \lambda=0.388\ A

(c) \lambda=0.038\ A

Explanation:

Given that,

(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

Where

m and e are the mass of and charge on an electron

On solving,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

V = 100 V

\lambda=\dfrac{12.27}{\sqrt{100} }\ A

\lambda=1.227\ A

(b) V = 1 kV = 1000 V

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{1000} }\ A

\lambda=0.388\ A

(c) If V=100\ kV=10^5\ V

\lambda=\dfrac{12.27}{\sqrt{10^5} }\ A

\lambda=0.038\ A

Hence, this is the required solution.

7 0
3 years ago
I will mark you brainlist please help!
Studentka2010 [4]

Answer:

C.) The Distance DH = 1.5 lambda

Explanation:

This statement C.) is false, because it does not count as the 1.5 wavelength, it is less than 1 wavelength.

7 0
3 years ago
Air enters a compressor with a pressure of 14.7 lbf/in.2 , a temperature of 70F, and a volumetric flow rate of 40 ft3 /s. Air ex
disa [49]

Answer:

210 hp

Explanation:

See attached picture.

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3 years ago
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