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denpristay [2]
3 years ago
14

A simple pendulum consists of a 4.9-kg mass attached to a string. The pendulum is pulled to the right and held at rest so that i

t is 2.08 m above the lowest point in its swing. If you let it go from this point, how fast (in m/s) is it traveling at the lowest point of its swing (on the initial pass)
Physics
1 answer:
aniked [119]3 years ago
8 0

Answer:

6.384 m/sec^{2}

Explanation:

The velocity is given by;

We know;

PE= mgh

KE= 1/2 mV^{2}

but KE=PE

==> 1/2 mV^{2} =mgh

==> 1/2 V^{2} =gh

==> v=\sqrt{2gh}

puting g=9.8 m/sec2

h=2.08 m

==> v= 6.384 m/sec^{2}=

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Answer:

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