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Mazyrski [523]
3 years ago
10

Nathan and his brother Zach love to play video games. Right

Mathematics
1 answer:
Monica [59]3 years ago
3 0

Answer:

N=2Z-11

\begin{array}{cc}\text{Zac's score}&\text{Natan's score}\\ 6&1\\7&3\\8&5\\9&7\end{array}

Step-by-step explanation:

Nathan's score is 11 less than 2 times Zac's score.

Let Z points be Zac's score and N points be Natan's score. then

2 times Zac's score = 2Z

11 less than 2 times Zac's score = 2Z -11

So, N = 2Z - 11

1. If Z=6, then N=2\cdot 6-11=12-11=1

2. If Z=7, then N=2\cdot 7-11=14-11=3

3. If Z=8, then N=2\cdot 8-11=16-11=5

4. If Z=9, then N=2\cdot 9-11=18-11=7

Thus, four other possibilities are

\begin{array}{cc}\text{Zac's score}&\text{Natan's score}\\ 6&1\\7&3\\8&5\\9&7\end{array}

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suter [353]
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2 years ago
What conclusions can be drawn using the given and its diagram?
dem82 [27]

Answer:

Whichever reasoning processes and research methods were used, the final conclusion is critical, determining success or failure. If an otherwise excellent experiment is summarized by a weak conclusion, the results will not be taken seriously.

Success or failure is not a measure of whether a hypothesis is accepted or refuted, because both results still advance scientific knowledge.

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little info

Step-by-step explanation:

hope this help

pick me as the brainliest

8 0
3 years ago
Help me pleaseee!!!!!
Oksi-84 [34.3K]

Answer:

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5 0
2 years ago
After releasing of radioactive material into.The atnosphere from.A nuclear.Powe plant in a country in 1988, the hay in that coun
Radda [10]

Answer:

the question is incomplete, so I looked for a similar one:

<em>After the release of radioactive material into the atmosphere  from a nuclear power plant, the hay was contaminated by iodine  131 ( half-life, 8 days). If it is all right to feed the hay to cows  when 10% of the iodine 131 remains, how long did the farmers  need to wait to use this hay? </em>

iodine's half life (we are given x, we need to find b):

0.5A₀ = A₀eᵇˣ

x = 8 days

we eliminate A₀ from both sides

0.5 = eᵇ⁸

ln 0.5 = ln eᵇ⁸

-0.69315 = b8

b = -0.69315 / 8 = -0.08664

since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):

0.1A₀ = A₀eᵇˣ

0.1 = eᵇˣ

ln 0.1 = bx

where b = -0.08664

x = ln 0.1 / -0.08664  = -2.302585 / -0.08664  = 26.58 days

4 0
3 years ago
Simplify the expression a^b: 5x^4 y^2 * 3x^6 y^9
tatyana61 [14]

Answer:

3x(3x + 2)

Step-by-step explanation:

(4x2 - 2x) - (-5x2 - 8x)

= 4x2 - 2x + 5x2 + 8x.

= 4x2 + 5x2 - 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

I hope it is right.

4 0
3 years ago
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