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nlexa [21]
3 years ago
14

PLZ HELP E!!!!!!! WILL MARK BRAINLIEST

Mathematics
1 answer:
vitfil [10]3 years ago
7 0

Answer:

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

)

Start on the left side.

1

+

sec

2

(

x

)

sin

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

+

1

cos

2

(

x

)

sin

2

(

x

)

Write  

sin

2

(

x

)

as a fraction with denominator  

1

.

1

+

1

cos

2

(

x

)

⋅

sin

2

(

x

)

1

Combine.

1

+

1

sin

2

(

x

)

cos

2

(

x

)

⋅

1

Multiply  

sin

(

x

)

2

by  

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

⋅

1

Multiply  

cos

(

x

)

2

by  

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

Apply Pythagorean identity in reverse.

1

+

1

−

cos

2

(

x

)

cos

2

(

x

)

Simplify.

Tap for more steps...

1

cos

2

(

x

)

Now consider the right side of the equation.

sec

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

2

cos

2

(

x

)

One to any power is one.

1

cos

2

(

x

)

Because the two sides have been shown to be equivalent, the equation is an identity.

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

)

is an identity

Step-by-step explanation:

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mars1129 [50]

Answer:

see explanation

Step-by-step explanation:

Given

\frac{14}{x} = \frac{56}{16} ( cross- multiply )

56x = 14 × 16 = 224 ( divide both sides by 56 )

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6 0
3 years ago
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vesna_86 [32]

The first one you have \frac{15}{24}=\frac{x}{3} . To solve this you would multiply both sides by 3.

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The second one you have \frac{7}{24}=\frac{3}{x} . To solve this you would multiply both sides by x.

\frac{7}{24}x=3

Now you would divide both sides by \frac{7}{24}.

x=\frac{3}{\frac{7}{24}}

You now then multiply 3 by 24 and then divide by 7.

\frac{72}{7}

x=\frac{72}{7} (in a mixed fraction would be 10\frac{2}{7})

6 0
3 years ago
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Lapatulllka [165]

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4 0
3 years ago
Find AM in the parallelogram if PN =15 and AO = 6. The diagram is not to scale.
valentinak56 [21]

Answer:

6

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

The diagonals are PN and MO. The point A divides PN into 2 equal segments as well as MO into 2 equal segments.

Since AO = 6, MA should also be equal. Hence, MA (or AM) = 6.

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3 years ago
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Doss [256]
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4 0
3 years ago
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