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3 years ago

HELP HELP ASAP!!! ANYONE ANYONE

Mathematics

1 answer:

AnnyKZ [126]3 years ago

3 0

Answer:

Step-by-step explanation:

factor each total

27 = 3 x 3 x 3

18 = 3 x 3 x 2

45 = 3 x 3 x 5

The largest (and only) common factor is 3

however each factorization also contains the product 3 x 3 = 9

so the maximum each bag may have cost is $9 and if so, she sold 5 bags of sugar cookies.

another option would be that each bag cost $3 and she sold 15 bags of sugar cookies. However, the question asked for the maximum possible price.

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A sales associate at a local boutique sold a jacket for $200 less a 10% discount.What is the discount (savings) on the jacket?

vampirchik [111]

The discount is $ 20 for the jacket hope that helps!

3 0

3 years ago

Help please I'm almost done

LUCKY_DIMON [66]

Simple....

3x-10(x+2)=13-7x

Just solve for x.....

3x-10x-20=13-7x

-7x-20=13-7x
+7x +7x

-20=13

NO SOLUTION.

Thus, your answer.

6 0

3 years ago

Read 2 more answers

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

4 years ago

iren [92.7K]

Answer:

Part A: The price of fuel A is decreasing by 12% per month.

Part B: Fuel A recorded a greater percentage change in price over the previous month.

Explanation:

Part A:

The function $f(x)=2.27(0.88)^x$ calculates the price of fuel A each month by multiplying the price of the month before by 0.88.

Month price, f(x)

1 2.27 (0.88) = 1.9976 ≈ 2.00

2 2.27(0.88)² = 1.59808 ≈ 1.60

3 2.27(0.88)³ = 1.46063 ≈ 1.46

Then, the price of fuel A is decreasing.

The percentage per month is (1 - 0.88) × 100 = 12%, i.e. the price decreasing by 12% per month.

Part B.

Table:

m price, g(m)

1 3.44

2 3.30

3 3.17

4 3.04

To find if the function decreases with a constant ration divide each pair con consecutive prices:

ratio = 3.30 / 3. 44 = 0.959 ≈ 0.96

ratio = 3.17 / 3.30 = 0.960 ≈ 0.96

ratio = 3.04 / 3.17 = 0.959 ≈ 0.96

Thus, the price of fuel B is decreasing by (1 - 0.96) × 100 =4%.

Hence, the fuel A recorded a greater percentage change in price over the previous month.

5 0

3 years ago

Please help I will reward brailiest

sergiy2304 [10]

Answer:

J is the possible answer

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers