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Hitman42 [59]
3 years ago
14

Simplify 72b^6/225 Everything is under one large square root?

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0
Here two ways

1. 8/25b^6
or

2. 0.32b^6
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What is the equation of the parabola?
irina1246 [14]

Because the parabola opens down and the vertex is at (0, 5), we conclude that the correct option is:

y  = -(1/8)*x² + 5.

<h3>Which is the equation of the parabola?</h3>

The relevant information is that we have the vertex at (0, 5), and that the parabola opens downwards.

Remember that the parabola only opens downwards if the leading coefficient is negative. Then we can discard the two middle options.

Now, because the parabola has the point (0, 5), we know that when we evaluate the parabola in x = 0, we should get y = 5.

Then the constant term must be 5.

So the correct option is the first one:

y  = -(1/8)*x² + 5.

If you want to learn more about parabolas:

brainly.com/question/4061870

#SPJ1

3 0
2 years ago
A tangent to a circle passes through the center of the circle<br>True<br>false<br>sometimes true​
liberstina [14]

Answer:

False.

Step-by-step explanation:

A tangent is a line that only touches exactly one point of the circle. (The outer edge) :)

8 0
3 years ago
A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t2 + 84t gives the rock's height in
kenny6666 [7]

Answer:

h = 110.24 m

Step-by-step explanation:

It is given that,

A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t^2 + 84t gives the rock's height in feet after t second.

We need to find the maximum height of the rock. For maximum height put \dfrac{dh}{dt}=0

So,

\dfrac{d( -16t^2 + 84t)}{dt}=0\\\\-32t+84=0\\\\t=\dfrac{84}{32}\\\\t=2.62\ s

Put t = 2.62 s in the equation of height. So,

h = -16(2.62)^2 + 84(2.62)\\\\h=110.24\ m

So, the maximum height of the rock is 110.24 m.

7 0
3 years ago
Solve the equation for y.
gayaneshka [121]

Answer: C

Step-by-step explanation:

2x+5y=5

\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}

2x+5y-2x=5-2x

\mathrm{Simplify}

5y=5-2x

\mathrm{Divide\:both\:sides\:by\:}5

\frac{5y}{5}=\frac{5}{5}-\frac{2x}{5}

\mathrm{Simplify}

\bf{y=-\frac{2}{5}x  + 1}

6 0
2 years ago
Find the range for the measures for the third side of a triangle with the given measures of two sides. 14 and 23
liberstina [14]

Given:

Two sides of a triangle are 14 and 23.

To find:

The angle for the measures for the third side of a triangle.

Solution:

If a, b, c are three sides of a triangle, then

a+b>c

a+c>b

b+c>a

It is given that two sides of a triangle are 14 and 23.

Let the third side of the given triangle be c. Then, using the above inequalities, we get

a+b>c

14+23>c

37>c                 ...(i)

Similarly,

a+c>b

14+c>23

c>23-14

c>9                 ...(ii)

And,

b+c>a

23+c>14

c>14-23

c>-9                 ...(iii)

Using (i), (ii) and (iii), we get

9

Therefore, the range for third side of the triangle is 9.

7 0
3 years ago
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