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Katyanochek1 [597]
3 years ago
6

Can someone please help me with these questions?

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Expanded form is writing out everything and no simplifying.

A. c times c

B. t times t times t times t  

C. 2 times x times x times x  

D. 4 times 4 times h times h

E. 2 times 2 times 2 times l times l times l

F. a times a times a + 7 times b times b

Hope this helps :)

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A racehorse weighs 490 kilograms. How much does it weigh in grams?
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Answer:

490,000 grams

Step-by-step explanation:

To convert from kilograms to grams - multiply the number of kilograms by 1000. (there are 1000 grams in a kilogram)

490 * 1000 = 490,000

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Solve 2-6(1-x)=6-4(-x-2) for x
OLEGan [10]

Answer:

x = 9

Step-by-step explanation:

Simplifying

2 + -6(1 + -1x) = 6 + -4(-1x + -2)

2 + (1 * -6 + -1x * -6) = 6 + -4(-1x + -2)

2 + (-6 + 6x) = 6 + -4(-1x + -2)

Combine like terms: 2 + -6 = -4

-4 + 6x = 6 + -4(-1x + -2)

Reorder the terms:

-4 + 6x = 6 + -4(-2 + -1x)

-4 + 6x = 6 + (-2 * -4 + -1x * -4)

-4 + 6x = 6 + (8 + 4x)

Combine like terms: 6 + 8 = 14

-4 + 6x = 14 + 4x

Solving

-4 + 6x = 14 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.

-4 + 6x + -4x = 14 + 4x + -4x

Combine like terms: 6x + -4x = 2x

-4 + 2x = 14 + 4x + -4x

Combine like terms: 4x + -4x = 0

-4 + 2x = 14 + 0

-4 + 2x = 14

Add '4' to each side of the equation.

-4 + 4 + 2x = 14 + 4

Combine like terms: -4 + 4 = 0

0 + 2x = 14 + 4

2x = 14 + 4

Combine like terms: 14 + 4 = 18

2x = 18

Divide each side by '2'.

x = 9

Simplifying

x = 9

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125+220+c=x
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The circumference of a particular species of tree was thought to be different depending on certain geographical factors. An SRS
Aleksandr-060686 [28]

Based on the information given, the most probable answer to this question is that the result is significant in its effect. The observed and examined variables generated a high probability which means that there is an observed effect.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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