Answer:
The velocity of the leaf relative to the jogger is 5 m/s.
Explanation:
Given that,
Velocity of jogger wrt to the ground, ![V_j=7\ m/s](https://tex.z-dn.net/?f=V_j%3D7%5C%20m%2Fs)
velocity of leaf wrt the ground, ![v_i=2\ m/s](https://tex.z-dn.net/?f=v_i%3D2%5C%20m%2Fs)
We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :
![V=v_j-v_i\\\\V=7-2\\\\V=5\ m/s](https://tex.z-dn.net/?f=V%3Dv_j-v_i%5C%5C%5C%5CV%3D7-2%5C%5C%5C%5CV%3D5%5C%20m%2Fs)
So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.
Explanation:
Mass of the crate, m = 68 kg
We need to find the resulting acceleration if :
(a) Force, P = 0
P = m a
⇒ a = 0
(b) P = 181 N
![a=\dfrac{P}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BP%7D%7Bm%7D)
![a=\dfrac{181\ N}{68\ kg}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B181%5C%20N%7D%7B68%5C%20kg%7D)
![a=2.67\ m/s^2](https://tex.z-dn.net/?f=a%3D2.67%5C%20m%2Fs%5E2)
(c) P = 352 N
![a=\dfrac{P}{m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BP%7D%7Bm%7D)
![a=\dfrac{352\ N}{68\ kg}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B352%5C%20N%7D%7B68%5C%20kg%7D)
![a=5.17\ m/s^2](https://tex.z-dn.net/?f=a%3D5.17%5C%20m%2Fs%5E2)
Hence, this is the required solution.
Answer:
3°C
Explanation:
We can that heat Q=m
dT
Where m is the mass
= specific heat capacity
dT = Temperature difference
here we have given m=625 g =.625 kg
specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)
=25°C
we have to find
we have also given Q=10.9 KJ
10.9=0.625×0.79×(25-
)
25-
=22
=3°C
Answer:
distance is meters, time is seconds