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kaheart [24]
4 years ago
14

An object has a mass of 0.250 kg. What is the gravitational force of on the object by the earth?

Physics
1 answer:
sesenic [268]4 years ago
7 0

Answer:

2.4525 N

Explanation:

The earths gravity is 9.81 N/Kg

And so to work this out you would multiply 9.81 by 0.250 which equals to 2.4525N

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Which substance has the least density? A. an iceberg B. a gallon of water C. a block of aluminum D. a small piece of lead
GREYUIT [131]

B. A gallon of water

8 0
3 years ago
A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up wit
Andru [333]

Hi there!

Recall:

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.

Plug in the givan values:

Δp = 1.5(-10 - 12) = -33 Ns

**OR, the magnitude: |-33| = 33 Ns

3 0
2 years ago
A two-tailed hypothesis test is used to evaluate __________. A. only a nondirectional hypothesis B. both a nondirectional and di
givi [52]

Answer;

B. both a non-directional and directional hypothesis

Explanation;

A two-tailed test is the standard test of significance to determine if there is a relationship between variables in either direction. Two-tailed tests do this by dividing the .05 in two and putting half on each side of the bell curve.

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6 0
3 years ago
Read 2 more answers
Awanita is placing items on a shelf that is 200 cm above the ground. She exerts a force of 20 N to lift a box from the floor to
Snowcat [4.5K]
The answer is 8 W. hope it helps
3 0
3 years ago
Read 2 more answers
A 7.25 kg7.25 kg block is sent up a ramp inclined at an angle ????=28.5°θ=28.5° from the horizontal. It is given an initial velo
Free_Kalibri [48]

Answer:

15.03 m

Explanation:

Given:

mass of the block, m = 7.25 kg

Angle, Θ = 28.5°

Initial speed of the block, v₀ = 15 m/s

let the distance traveled by the block be 's'

Now, applying the work energy theorem,

we have

(m\times g\times\sin(\theta)\times s) + \mu_k\times mg\times s\times cos(\theta) = \frac{1}{2}\times m\times v^2

on substituting the values in the above equation, we get

(7.25\times 9.8\times\sin(28.5^o)\times s) + 0.326\times 7.25\times9.8\times s\times cos(28.5^o) = \frac{1}{2}\times 7.25\times 15^2

or

33.902\times s) +20.35\times s = 815.625

or

54.252\times s = 815.625

s = 15.03 m

Hence, the block will travel 15.03 m up the ramp

6 0
3 years ago
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