Well both ends of the magnet have a diffrent magnetic force. i hope this was the answer you where looking for, and have a nice rest of the day
Answer:
Random errorrs
1) Variations in the level of the eye when we measure the dimensions of the cubic piece using the metric rule.
2) Possible vibrations or disbalance when we measure the mass of the of the cylinder.
Systematic errors
3) Wrong calibration for the balance and that represent a measurement wrong
Explanation:
Previous concepts
Random error represent an statistical error associated to the effect random in the experiment.
Systematic error is a "repeatable error associated with faulty equipment or a flawed experiment design", so is an error non controlled.
Solution to the problem
So as we can see we have two possible types of errors : random and systematic errors. For this stuation the list of 3 errors required are:
Random errors
1) Variations in the level of the eye when we measure the dimensions of the cubic piece using the metric rule.
2) Possible vibrations or disbalance when we measure the mass of the of the cylinder.
Systematic errors
3) Wrong calibration for the balance and that represent a measurement wrong
First you get a tool and remove some of the warping from the tip.hehe. Then you neatly wrap the wires around the nail. Wrap more if you want to make it stronger. Make sure your able to fit the battery. connect the end of the wire to the positive side. Be careful.
Answer:
15.68 m/s
Explanation:
Given that,
She catches the ball 3.2 s later at the same height from which it was thrown.
When it reaches the maximum height, its height is equal to 0.
It will move under the action of gravity.
2 here comes for the time of ascent and descent.
So,
So, the initial upward speed of the ball is 15.68 m/s.
Answer:
We need to multiply 12 to each term to eliminate fractions.
Explanation:
Given expression:
To eliminate the fraction we need to multiply each term by least common multiple of the denominators of the fraction.
The denominators in the above expressions are:
4, 3 and 2
The multiples of each can be listed below.
2⇒ 2,4,6,8,10,<u>12</u>,14,16.....
3⇒ 3,6,9,<u>12</u>,15,18
4⇒ 4,8,<u>12</u>.......
From the list of the multiples stated, we can see the least common multiple is 12.
So we will multiply each term by 12.
Multiplying 12 to both sides.
Using distribution,
Thus we successfully eliminated the fractions.
