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stira [4]
3 years ago
9

The point (4, -3) is on the graph of which function PLEASE HELP

Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

Equation B

Step-by-step explanation:

Ask yourself:  Does (4, -3) satisfy any of the four possible answer choices?

B is correct, because (1/2)(4) - 5 does equal -3:

2 - 5 = -3.  YES

You might be interested in
One-third of a number b multiplied by -11 is more than 3 2
jarptica [38.1K]
\frac{b}{3}\times(-11)>\frac{2}{3}

5 0
1 year ago
Find the value of X in the picture please
slamgirl [31]

Answer:

The measure of arc x is 70°

Step-by-step explanation:

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

and

The inscribed angle is half that of the arc it comprises.

so

The arc that comprises the inscribed angle of 15 degrees is equal to

15(2)=30 degrees

The outer angle of 20 degrees is equal to

20°=(1/2)[x-30°]

40°=[x-30°]

x=40°+30°=70°

8 0
4 years ago
PLEASE HELP WILL MARK BRAINLIEST AND GIVE 50 POINTS
Alexeev081 [22]

Answer:

The correct option is;

e. 2500

Step-by-step explanation:

The formula for sample size is given by the following formula;

n = \dfrac{z^2 \times \hat p(1 - \hat p)}{\epsilon ^2}

At 95%, z = 1.96

ε = Margin of error = 0.02 = 2%

Finding the sample size, n, given only the margin of error is by the following formula;

Margin of error = 100/√n

Therefore, we have;

2 = 100/√n

√n = 100/2 = 50

n = 50² = 2500

Therefore, the correct option is e. 2500.

4 0
3 years ago
F(x)=x^2-3x+18 how many distinct real number zeros does f have?
vampirchik [111]

Answer:

None of the distinct real number zeros the function have.

Step-by-step explanation:

Considering the function

f(x)=x^2-3x+18

The zeroes of a function are those values that touches the x-axis. In order to find those values we must

Set  f(x) = 0 in order to find those values

0=x^2-3x+18

\mathrm{Switch\:sides}

x^2-3x+18=0

\mathrm{Solve\:with\:the\:quadratic\:formula}

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=18:\quad x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{-\left(-3\right)+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

As

3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}=3+\sqrt{63}i

so

x=\frac{3+\sqrt{63}i}{2\cdot \:1}

x=\frac{3+3\sqrt{7}i}{2}

x=\frac{3}{2}+\frac{3\sqrt{7}}{2}i

Similarly,

x=\frac{-\left(-3\right)-\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}:\quad \frac{3}{2}-i\frac{3\sqrt{7}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3}{2}+i\frac{3\sqrt{7}}{2},\:x=\frac{3}{2}-i\frac{3\sqrt{7}}{2}

BUT, NONE OF THEM ARE REAL NUMBER ZEROS.

Therefore, none of the distinct real number zeros the function have.

5 0
4 years ago
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)° <br> What is FJH
Kitty [74]

Hello from MrBillDoesMath!

Answer:

60

Discussion:

As JG bisects FJG,  

FJG     = GJH                =>

2x + 4 = 3x-9                => subtract 2x from each side

4         = 3x -2x - 9        => simplify

4         = x - 9                => add 9 to both sides

4 + 9   = x

x = 13

Now, FJH =

FJG        + GJH

(2x + 4)  + (3x-9) =

5x -5                             => substitute x 13

5(13) -5  =

65 - 5 =

60

Thank you,

MrB

5 0
3 years ago
Read 2 more answers
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