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stira [4]
3 years ago
9

The point (4, -3) is on the graph of which function PLEASE HELP

Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

Equation B

Step-by-step explanation:

Ask yourself:  Does (4, -3) satisfy any of the four possible answer choices?

B is correct, because (1/2)(4) - 5 does equal -3:

2 - 5 = -3.  YES

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line segment eg is partitioned by point f in the ratio 1:1. point e is at e (0, 4), and point f is at (1, 3). what are the coord
damaskus [11]

The coordinates of G (x₂ , y₂) for line segment EG = (2,2).

As given:

Line segment EG

Partitioned point of line segment is F

Coordinates of F (x ,y)=(1,3) and E (x₁ ,y₁)=(0,4)

Let coordinate of G (x₂ , y₂)

Ratio m:n =1:1

(x ,y) ={ ( mx₂ +nx₁ )/ (m +n) , ( my₂ +n y₁ )/ (m +n)

⇒(1,3) = {(1x₂ +1(0) )/2 , 1y₂ +1(4) /2}

⇒x₂ =2, y₂ =2

Therefore, the coordinates of G (x₂ , y₂) for the given line segment is equal to (2,2).

   

Learn more about line segment here

brainly.com/question/25727583

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6 0
2 years ago
8^15÷8^−3 im lost i dont get this whole simply thing at all
Phantasy [73]

8^15 ÷ 1/8^3 = 8^15 x 8^3=8^18

8 0
4 years ago
Read 2 more answers
Need Help With Functions. Screenshot attatched
FinnZ [79.3K]

Answer:

4x² -29x +51

Step-by-step explanation:

Put x-3 where x is in the original function definition, then "simplify". I think you'll find it convenient to rewrite the original function definition first.

... g(x) = 4x² -5x = x(4x -5)

Substituting, we have

... g(x-3) = (x -3)(4(x -3) -5)

... = (x -3)(4x -17) . . . . . simplify right factor

... = 4x² -12x -17x +51

... g(x -3) = 4x² -29x +51

3 0
3 years ago
Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .
KIM [24]

Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.

If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0                    [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k)  = 0               [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k              -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

\frac{v}{|v|}

Where;

|v| = \sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}

|v| = \sqrt{17(v_3)^2 + (v_2)^2}

\frac{v}{|v|} = \frac{4v_3i + v_2j + v_3k}{\sqrt{17(v_3)^2 + (v_2)^2}}

This is the general form of all unit vectors that are orthogonal to vector u

where v₂ and v₃ are non-zero arbitrary real numbers.

3 0
3 years ago
One computer printer can print a company's weekly payroll checks in 60 min. A second
Fed [463]

35 mins is the answer.

1/2 +1/3 = 5/6 = 30mins

1/6 remaining is distributed over 5 mins

30/6 =5

30+5 = 35mins

3 0
3 years ago
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