Answer : -4.65 °C
Explanation : On solving the sum w.r.t to water as the aqueous solvent in solution;
(101.28°C - 100°C) / (0.512 c/m) = 2.5 m,
Now, 2.5 m X (1.86 °C/m) = 4.65 °C which will be the change in temperature of the solution in °C;
To find the freezing point we have to get it subtracted by 0°C
0°C - 4.65°C = -4.65°C
Answer:
The new volume of the gas is 32L
Explanation:
P1 = 16atm
V1 = 4L
P2 = atm
V2 = ?
According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.
P1 * V1 = P2 * V2
V2 = (P1 * V1) / P2
V2 = (16 * 4) / 2
V2 = 64 / 2
V2 = 32L
The new volume of the gas is 32L
<h3>Answer:<u><em>What organism is responsible for the cycling of nitrogen?</em></u></h3><h3><em><u /></em></h3><h3>Explanation:<u><em>Bacteria</em></u></h3><h3><u><em>Bacteria play a key role in the nitrogen cycle.</em></u></h3><h3><u><em>Some species of nitrogen-fixing bacteria are free-living in soil or water, while others are beneficial symbionts that live inside of plants.</em></u></h3><h3><em><u /></em></h3>
Answer:
552 g of LiNO₃
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 2 L
Molarity of LiNO₃ = 4 M
Mass of LiNO₃ =?
Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:
Volume of solution = 2 L
Molarity of LiNO₃ = 4 M
Mole of LiNO₃ =?
Molarity = mole /Volume
4 = mole of LiNO₃ / 2
Cross multiply
Mole of LiNO₃ = 4 × 2
Mole of LiNO₃ = 8 moles
Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:
Mole of LiNO₃ = 8 moles
Molar mass of LiNO₃ = 7 + 14 + (16×3)
= 7 + 14 + 48
= 69 g/mol
Mass of LiNO₃ =?
Mole = mass /Molar mass
8 = Molar mass of LiNO₃ /69
Cross multiply
Molar mass of LiNO₃ = 8 × 69
Molar mass of LiNO₃ = 552 g
Thus, 552 g of LiNO₃ is needed to prepare the solution.
