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pychu [463]
3 years ago
15

A great white shark has resided at a depth where the pressure is 16 atm. If the initial volume of its swim bladder is 4 L, what

would the new volume be if it surfaces where the pressure is 2 atm
Chemistry
1 answer:
padilas [110]3 years ago
6 0

Answer:

The new volume of the gas is 32L

Explanation:

P1 = 16atm

V1 = 4L

P2 = atm

V2 = ?

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (16 * 4) / 2

V2 = 64 / 2

V2 = 32L

The new volume of the gas is 32L

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What is the ph of a buffer prepared by adding 0.809 mol of the weak acid ha to 0.608 mol of naa in 2.00 l of solution? The disso
Anarel [89]

The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247

The pH of the buffer can be known as

pH = pK_{a} + log[\frac{[A-]}{[HA]}}]

The concentration of [A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\

Similarly, the concentration of [HA] = \frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404

Then the pH of the buffer will be

pH = 6.247 + log [ 0.304/0.404]

pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236

So, the pH of the buffer is 6.1236.

5 0
3 years ago
a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is
NeX [460]

Answer:

The specific heat of iron is 0.45 J/g.°C

Explanation:

The amount of heat absorbed by the metal is given by:

heat = m x Sh x ΔT

From the data, we have:

heat = 180.8 J

mass = m = 22.44 g

ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C

Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT)  = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

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Answer:

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Explanation:

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