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34kurt
3 years ago
11

What is the probability of randomly selecting an odd number from the numbers 1 - 15?

Mathematics
1 answer:
Darya [45]3 years ago
5 0

Answer:

7/15 Hope it helps

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 0
3 years ago
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Simplify each algebraic expression.
GREYUIT [131]

Answer:

\huge\boxed{\sf-2x+28}\\\\\huge\boxed{\sf 10x-4}\\\\\huge\boxed{\sf 56-5x}\\\\\huge\boxed{\sf x-13}

Step-by-step explanation:

\sf 2x + 4(7-x)  \\\\Resolving \ Parenthesis\\\\2x + 28-4x \\\\Combining\ like\ terms\\\\2x-4x +28\\\\-2x + 28\\\\\rule[225]{225}{2}

\sf \\12x-(4+2x)\\\\12x-4-2x\\\\Combining \ like \ terms\\\\12x-2x - 4\\\\10x-4 \\\\\rule[22]{225}{2} \\2(10-x)+3(12-x) \\\\Resolving \ Parenthesis\\\\20-2x + 36 -3x\\\\Combining \ like \ terms\\\\20+36 -2x-3x\\\\56 - 5x \\\\\rule[225]{225}{2}

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Hope this helped!

~AnonymousHelper1807

3 0
3 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Blababa [14]

Answer:

0.3707

Step-by-step explanation:

Mean length = 30.05 inches

Standard deviation = 0.3 inches

We are supposed to find the probability that the average length of a steel sheet from a sample of 9 units is more than 29.95 inches long

Formula : Z=\frac{x-\mu}{\sigma}

\mu = 30.05\\\sigma = 0.3

x= 29.95

Substitute the values :

Z=\frac{29.95-30.05}{0.3}

Z=-0.33

Refer the z table for p value

p value = 0.3707

So, the probability that the average length of a steel sheet from a sample of 9 units is more than 29.95 inches long is 0.3707

3 0
3 years ago
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AVprozaik [17]

Answer:

10 miles

Step-by-step explanation:

Right triangle

a^2 + b^2 = c^2

6^2 + 8^2 = c^2

36 + 64 = c^2

Sqrt 100 = c

C = 10

8 0
3 years ago
I need the question below answer
MAVERICK [17]

Answer:

school

Step-by-step explanation:

6 0
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