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Rufina [12.5K]
3 years ago
10

Which expressions are equivalent to the one below? Check all that apply 10^x

Mathematics
1 answer:
Lyrx [107]3 years ago
6 0

A, C, and D are equal to 10^x

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Please help me asap​
omeli [17]

Answer:

-.51, .1/2, .42, 11/20

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
Multiply. Write your answer as a fraction in simplest form.<br><br> 2/15 x 9
Mkey [24]

Answer:

6 /5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Systems of equations and inequalities<br> solving systems by elimination<br> {y= -x+1<br> {y= 4x-14
kodGreya [7K]

Answer:

x = 3  , y = -2

Step-by-step explanation:

Solve the following system:

{y = 1 - x | (equation 1)

y = 4 x - 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 3  , y = -2

5 0
3 years ago
Read 2 more answers
Solve the following equations.<br> log6(x) = 1
Ksenya-84 [330]

Answer:

x = 6

Step-by-step explanation:

Given:

log₆(x) = 1

Now,

From the properties of log

logₓ (z)= \frac{\log(z)}{\log(x)}  (where the base of the log is equal for both numerator and the denominator)

also,

log(xⁿ) = n × log(x)

thus,

using the above properties, we can deduce the results as:

logₓ(y) = n is equivalent to y = xⁿ

therefore,

the given equation can be deduced as:

log₆(x) = 1

into,

x = 6¹

or

x = 6

7 0
3 years ago
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