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Gekata [30.6K]
2 years ago
11

Dilations He said she said

Mathematics
1 answer:
marissa [1.9K]2 years ago
8 0

Answer:

the answer should be Annie

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Which two values of x are roots of the polynomial below? x^2-3x+5
Gemiola [76]

Given:

Polynomial x^2-3x+5

To find:

The values of x.

Solution:

x^2-3x+5=0

Quadratic equation formula:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here a=1, b=-3, c=5.

Substitute the values in the formula, we get

$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}

$x=\frac{3 \pm \sqrt{9-20}}{2}

$x=\frac{3 \pm \sqrt{-11}}{2}

$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}

Option E and option F are the roots of the polynomial.

The values of x are x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}.

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