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Sholpan [36]
3 years ago
9

Difference between elastic and inelastic collisions

Physics
1 answer:
Eva8 [605]3 years ago
3 0
An elastic collision<span> is where there is no loss of kinetic energy in the </span>collision<span>. Momentum is conserved saved in </span>inelastic collisions<span>, but cannot track the kinetic energy through the </span>collision<span> since some of it is changed into other forms of energy.</span>
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Acceleration is constant in free fall. So it would again be 9.8 m/s².

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How will you know if a molecule is coplanar?
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How does a person standing on the ground correctly explain why you, sitting on the left side of a slippery back car seat, slide
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Answer:

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2 years ago
A 85-kg astronaut is stranded from his space shuttle. He throws a 1-kg hammer away from the shuttle with a velocity of 17 m/s. H
algol [13]

Answer:

0.2 m/s

Explanation:

given,

mass of astronaut, M = 85 Kg

mass of hammer, m = 1 Kg

velocity of hammer , v =17 m/s

speed of astronaut, v' = ?

initial speed of the astronaut and the hammer be equal to zero = ?

Using conservation of momentum

(M + m) V = M v' + m v

(M + m) x 0 = 85 x v' + 1 x 17

85 v' = -17

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negative sign represent the astronaut is moving in opposite direction of hammer.

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4 0
3 years ago
If an ideal monatomic gas undergoes an adiabatic expansion, in which the volume increases by a factor of 4.0, by what factor doe
julsineya [31]

Answer:

e) 0.099

Explanation:

For an adiabatic expansion:

P_1 V_1^{\gamma} = P_2 V_2^{\gamma}

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

\gamma is the adiabatic index (which is \frac{5}{3} for an ideal monoatomic gas

In this problem, we have

V_2 = 4 V_1 since the volume increases by a factor 4

We can re-write the equation to find by what factor the pressure changes:

\frac{P_2}{P_1}=(\frac{V_1}{V_2})^{\gamma}=(\frac{V_1}{4V_1})^{5/3}=(\frac{1}{4})^{5/3}=0.099

8 0
3 years ago
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