Explanation:
As the given spheres are connected by a thin wire so, the potential on the spheres are the same.
......... (1)
Hence, total charge will be as follows.
= Q = -95.5 nC .......... (2)
Using the above two equations, the final equation will be as follows.
![q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}](https://tex.z-dn.net/?f=q_%7B2%7D%20%3D%20%5Cfrac%7BQr_%7B2%7D%7D%7Br_%7B1%7D%20%2B%20r_%7B2%7D%7D)
and, ![q_{1} = \frac{Qr_{1}}{r_{1} + r_{2}}](https://tex.z-dn.net/?f=q_%7B1%7D%20%3D%20%5Cfrac%7BQr_%7B1%7D%7D%7Br_%7B1%7D%20%2B%20r_%7B2%7D%7D)
Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.
![q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}](https://tex.z-dn.net/?f=q_%7B2%7D%20%3D%20%5Cfrac%7BQr_%7B2%7D%7D%7Br_%7B1%7D%20%2B%20r_%7B2%7D%7D)
= ![\frac{-95.5 \times 74.4 cm}{(11.5 + 74.4) cm}](https://tex.z-dn.net/?f=%5Cfrac%7B-95.5%20%5Ctimes%2074.4%20cm%7D%7B%2811.5%20%2B%2074.4%29%20cm%7D)
= 82.714 nC
Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.
<span> planetary satellites vary greatly in size, from very small, to some that are larger than some planets.</span>
Ok so I already studied this and I realized it was water or also Oxygen
Answer:
F_g = 372.78 N
Explanation:
Formula for force of gravity is;
F_g = mg
Where;
m is mass
g is acceleration due to gravity
We are given;
Mass = 38 kg
Acceleration due to gravity has a constant value of 9.81 m/s²
Thus;
F_g = 38 × 9.81
F_g = 372.78 N
I believe it’s B but i’m not sure