Answer:
I=0.0361 kg.m^2
Explanation:
Torque is the rotational equivalent of a force
Torque= perpendicular distance r X Force F
Torque T = I(moment of inertia) X α (angular acceleration)
T= Iα
r= 0.0285m
F= 1.9 x 10^3
T=0.0285 x 1.9 x 10^3
T= 54.15Nm
I=T/α
I=54.15/150
I=0.361 kg.m^2
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The change in velocity is +4 m/s to the right (or -4 m/s to the left).
The object's mass is irrelevant.
We know that a=vf_vi/t equals equation "a" . Where a is the acceleration of the body , vf is the final velocity , vi is the initial velocity and t is equal to time . Since vi equals o m/s , vf equals to 60 m/s and t equals 10 s. Put in equation "a". a=60-0/10 =6m/s2
To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as
F = ma
Where,
m= Mass
a = Acceleration
At the same time the frictional force can be defined as,

Where,
Frictional coefficient
N = Normal force (mass*gravity)
Our values are given as,

By condition of Balance the friction force must be equal to the total net force, that is to say



Re-arrange to find acceleration,



Therefore the acceleration the horse can give is 