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NemiM [27]
4 years ago
12

Two charges of 15 pC and −40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through

the surface of the cube.
Physics
1 answer:
Kobotan [32]4 years ago
4 0

To solve this problem, we will apply the concepts related to Gaus' law that establishes that the electric flow through a surface is given by the charge of the object on the Vacuum permittivity. Mathematically this would be

\phi = \frac{Q_{net}}{\epsilon_0}

We must bear in mind that the net charge with the difference of the two charges given, therefore, replacing,

\phi = \frac{(15-40)*10^{-12}C}{8.85*10^{-12}C^2/Nm^2}

\phi = 2.82WB

Negative sign indicate flux is inward the surface

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An electric dipole with its center located at the origin of a Cartesian coordinate system oscillates along the x axis, creating
Ainat [17]

Answer:

The wave propagates on the z axis and the polarization is linear on the x axis

Explanation:

Part A

When the two dipole charges oscillate they form a fluctuating wave that propagates in the perpendicular direction, so if the oscillation of the magnetic field is on the axis and the propagation of the wave occurs on the z-axis.

The polarization of the electric wave is equal to the direction of the electric field, therefore as the field oscillates on the x-axis the polarization is also on the x-axis and is linearly polarized.

Part B

The wave propagates on the z axis and the polarization is linear on the x axis

5 0
3 years ago
9.
katen-ka-za [31]

Answer:

Standard metric unit used for force is Newton

4 0
3 years ago
Read 2 more answers
g Two long parallel wires are a center-to-center distance of 2.50 cm apart and carry equal anti-parallel currents of 2.70 A. Fin
schepotkina [342]

Answer:

864 mT

Explanation:

The magnetic field due to a long straight wire B = μ₀i/2πR where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, i = current in wire, and R = distance from center of wire to point of magnetic field.

The magnitude of magnetic field due to the first wire carrying current i = 2.70 A at distance R which is mid-point between the wires is B = μ₀i/2πR.

Since the other wire also carries the same current at distance R, the magnitude of the magnetic field is B = μ₀i/2πR.

The resultant magnetic field at B is B' = B + B = 2B = 2(μ₀i/2πR) = μ₀i/πR

Now R = 2.50 cm/2 = 1.25 cm = 1.25 × 10⁻² m and i = 2.70 A.

Substituting these into B' = μ₀i/πR, we have

B' = 4π × 10⁻⁷ H/m × 2.70 A/π(1.25 × 10⁻² m)

B = 10.8/1.25 × 10⁻⁵ T

B = 8.64 × 10⁻⁵ T

B = 864 × 10⁻³ T

B = 864 mT

4 0
3 years ago
if i cut a body in half, after the application of heat to a body what will be the resultant temperature of the two halves
Leya [2.2K]

The temperature of both the halves of the body remain same and thus the body  remain in thermal equilibrium.

Both the parts of the body even after being in contact with each other will not transfer heat and thus maintain equal temperature and the resultant of the two will be zero.


6 0
4 years ago
Read 2 more answers
A light meter reports that a camera setting of 1125s at f/4.0 will give a correct exposure. But the photographer wishes to use f
nadezda [96]

Answer:

18000 seconds.

Explanation:

Focus to diameter ratio

\frac{f}{d_1}=4.0

Shutter time = T₁ = 1125 s

Changing the focus to diameter ratio gives us

\frac{f}{d_2}=16

Ratio of the areas

\frac{A_1}{A_2}=\frac{d_1^2}{d_2^2}\\\Rightarrow \frac{A_1}{A_2}=\frac{4^2}{16^2}\\\Rightarrow \frac{A_1}{A_2}=\frac{1}{16}

Amount of light is the product of time and area

\T_1A_1=T_2A_2}\\\Rightarrow T_2=T_1\frac{A_2}{A_1}\\\Rightarrow T_2=1125\times 16\\\Rightarrow T_2=18000\ seconds

Shutter speed will be 18000 seconds.

8 0
4 years ago
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