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NemiM [27]
3 years ago
12

Two charges of 15 pC and −40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through

the surface of the cube.
Physics
1 answer:
Kobotan [32]3 years ago
4 0

To solve this problem, we will apply the concepts related to Gaus' law that establishes that the electric flow through a surface is given by the charge of the object on the Vacuum permittivity. Mathematically this would be

\phi = \frac{Q_{net}}{\epsilon_0}

We must bear in mind that the net charge with the difference of the two charges given, therefore, replacing,

\phi = \frac{(15-40)*10^{-12}C}{8.85*10^{-12}C^2/Nm^2}

\phi = 2.82WB

Negative sign indicate flux is inward the surface

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Answer:

I=0.0361 kg.m^2

Explanation:

Torque is the rotational equivalent of a force

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Torque T = I(moment of inertia) X α (angular acceleration)

T= Iα

r= 0.0285m

F= 1.9 x 10^3

T=0.0285 x 1.9 x 10^3

T= 54.15Nm

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A 2kg object initially going 4m/s to the right is later going 8m/s. whats the change in velocity?
Nezavi [6.7K]

The change in velocity is +4 m/s to the right (or -4 m/s to the left).

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3 years ago
If a car increases its velocity from zero to 60 m/s in 10 seconds, its acceleration is
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We know that a=vf_vi/t equals equation "a" . Where a is the acceleration of the body , vf is the final velocity , vi is the initial velocity and t is equal to time . Since vi equals o m/s , vf equals to 60 m/s and t equals 10 s. Put in equation "a". a=60-0/10 =6m/s2
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A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration
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To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

F_f = \mu N

Where,

\mu = Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\

By condition of Balance the friction force must be equal to the total net force, that is to say

F_{net} = F_f

m_{total}a = \mu m_hg

(m_h+m_c)a = \mu*m_h*g

Re-arrange to find acceleration,

a= \frac{\mu*m_h*g}{(m_h+m_c)}

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a = 4.54 m/s^2

Therefore the acceleration the horse can give is 4.54m/s^2

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3 years ago
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