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Viefleur [7K]
4 years ago
8

What is evaporation​

Physics
2 answers:
Vinil7 [7]4 years ago
8 0

Answer: The process of liquid turning into the gas phase.

Explanation:

When liquid molecules collide, they transfer energy to one another.

Sergeeva-Olga [200]4 years ago
7 0
Evaporation is the process of a substance in a liquid state changing to a gaseous state due to an increase in temperature and/or pressure. Evaporation is a fundamental part of the water cycle and is constantly occurring throughout nature.
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Danielle exerts a 14.0 N force to compress a spring by a distance of 8.00 cm. What is the spring constant of this spring
Lady_Fox [76]

Answer:

175 N/m

Explanation:

Given:

Force = F=  14.0 N

Distance = x = 8.00 cm = 0.08 m

To find:

spring constant

Solution:

spring constant is calculated by using Hooke's law:

k =  F/x

Putting the values in above formula:

k = 14.0 / 0.08

k = 175 N/m

4 0
3 years ago
Astronaut Jill leaves Earth in a spaceship and is now traveling at a speed of 0.280c relative to an observer on Earth. When Jill
Slav-nsk [51]

(B) 1.00 m

Explanation:

Since the meter stick is traveling with Jill, it will have the same speed as she does so relative to Jill, the meter stick is stationary so its length remains 1.00 m as measured by her.

8 0
3 years ago
Three children are riding on the edge of a merry-go-round that is 182 kg, has a 1.60 m radius, and is spinning at 15.3 rpm. The
Korolek [52]

Answer:

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

Explanation:

The merry-go-round can be represented by a solid disk, whereas the three children can be considered as particles. Since there is no external force acting on the system, we can apply the principle of angular momentum conservation:

\left(\frac{1}{2}\cdot M + m_{1}+m_{2} + m_{3} \right)\cdot R^{2}\cdot \dot n_{o} = \left(\frac{1}{2}\cdot M + m_{1} + m_{3})\cdot R^{2}\cdot \dot n_{f} (1)

Where:

M - Mass of the merry-go-round, in kilograms.

m_{1}, m_{2}, m_{3} - Masses of the three children, in kilograms.

R - Radius of the merry-go-round/Distance of the children with respect to the center of the merry-go-round, in meters.

\dot n_{o}, \dot n_{f} - Initial and final angular speed, in revolutions per minute.

If we know that M = 182\,kg, m_{1} = 17.4\,kg, m_{2} = 28.5\,kg, m_{3} = 32.8\,kg, R = 1.60\,m and \dot n_{o} = 15.3\,\frac{rev}{min}, then the final angular speed of the system is:

\dot n_{f} = \dot n_{o}\cdot \left(\frac{\frac{1}{2}\cdot M + m_{1} + m_{2} + m_{3} }{\frac{1}{2}\cdot M + m_{1} + m_{3} } \right)

\dot n_{f} = \left(15.3\,\frac{rev}{min} \right)\cdot \left[\frac{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg +28.5\,kg + 32.8\,kg }{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg + 32.8\,kg } \right]

\dot n_{f} = 18.388\,\frac{rev}{min}

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

7 0
3 years ago
10. If the gravitational force between two objects of equal mass is found to be 4.60*10^-6 N when the objects are 15 meters apar
liraira [26]

Answer:

Explanation:

F = G*m1 * m2 / r^2

G = 6.67408 × 10-11 m3 kg-1 s-2

r = 15 m

F = 4.60 * 10^-6 N

m1 = m2 = m

F = 6.67 * 10^-11 * m^2 / 15^2

4.60 * 10^-6 = 6.67 * 10^-11 * m^2 / 225            Multiply both sides by 225

4.60*10^-6 * 225 = 6.67*10^-11 * m^2

.001035 =  6.67408 × 10-11 * m^2                     Divide by  6.67408 × 10-11

0.001035/ 6.67408 × 10-11 = m^2

m^2 = 15507755                                                Take the square root of both sides

m = sqrt(15507755   )

m = 3938 kg

5 0
3 years ago
a body has weight 20N how much force is required to move it vertically upwards with an acceleration of 2m/s​
kramer

<h2>Given :-</h2>

  • Weight = 20 N

  • Acceleration = 2 m/s

<h2>To Find :-</h2>

  • Force applied=?

<h2>Solution :-</h2>

As we know that,

<h3>F = ma</h3>

  • F is the Force applied
  • M is the Mass
  • A is the Acceleration

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

F = 20 × 2

F = 40 N

<h3>Hence :-</h3>

Force applied is 40 N

<h2>Know More :-</h2>

  • First equation of motion
  • v = u + at

  • Second equation of motion
  • s = ut + ½at²

  • Third Equation of motion
  • v² - u² = 2as

\begin{gathered} \\ \end{gathered}

3 0
3 years ago
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