All categories

3 years ago

If a car goes along a straight road heading east and speeds up from 45 ft/s to 60 ft/s in 5 s, calculate the acceleration.

1 answer:

8 0

<span>acceleration = change in velocity/ time = (final velocity - initial velocity)/time

accel = (60ft/s - 45ft/s)/5s = 3 ft/s</span>

You might be interested in

Two electronics technicians are discussing conductors and insulators. Technician A says that conductors have more free electrons

vitfil [10]

Technician A is Correct.

You can see this when he says that conductors have more free electrons than insulators. This statement is True.

While Technician B says that, insulators have the lower resistance than conductors. This statement is False.

4 0

3 years ago

Read 2 more answers

An unpolarized beam of light with an intensity of 4000 W/m2 is incident on two ideal polarizing sheets. If the angle between the

erastova [34]

Answer:

The intensity is $I_2 = 1654 \ W/m^2$

Explanation:

From the question we are told that

The intensity of the unpolarized light is $I_o = 4000 \ W/m^2$

The angle between the ideal polarizing sheet is $\theta = 0.429 \ rad = 0.429 * 57.296 = 24.58^o$

Generally the intensity of light emerging from the first polarizer is mathematically represented as

$I_2 = \frac{I_o}{2}$

substituting values

$I_1 = \frac{4000}{2}$

$I_1 = 2000 \ W/m^2$

Then the intensity of incident light emerging from the second polarizer is mathematically represented by Malus law as

$I_2 = I_1 cos^2 (\theta )$

substituting values

$I_2 = 2000 * [cos (24.58)]^2$

$I_2 = 1654 \ W/m^2$

4 0

3 years ago

Living organisms, such as people and other animals and our Earth's

cluponka [151]

Answer:

true

Explanation:

5 0

3 years ago

A sample of a gas in a rigid container at 30. 0°c and 2. 00 atm has its temperature increased to 40. 0°c. What will be the new p

Diano4ka-milaya [45]

Answer:

2.066 atm

Explanation:

PV = nRT increase T volume and n and R remain constant

30 C = 303.15 K 40 C = 313.15

P prop to T new P will be 313.15/303.15 * 2 atm = 2.066 atm

8 0

2 years ago

A 1.6-kg ball is attached to the end of a 0.40-m string to form a pendulum. This pendulum is released from rest with the string

Digiron [165]

Answer:

a. 1.5 m/s

Explanation:

We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:

$m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\$

where,

m₁ = mass of ball = 1.6 kg

m₂= mass of block = 0.8 kg

u₁ = initial speed of ball = 0 m/s

u₂ = initial speed of block = 0 m/s

v₁ = final speed of ball = ?

v₂ = final speed of block = 3 m/s

Therefore,

$(1.6\ kg)(0\ m/s)+(0.8\ kg)(0\ m/s)=(1.6\ kg)(v_{1})+(0.8\ kg)(3\ m/s)\\\\v_{1} = \frac{2.4\ N.s}{1.6\ kg}\\$

v₁ = 1.5 m/s

Therefore, the correct option is:

4 0

3 years ago