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maxonik [38]
3 years ago
11

This is urgent, please answer!!

Mathematics
1 answer:
Serhud [2]3 years ago
3 0
Answer: 23.4

Explanation: make the volumes equal each other with the ? as x. Then solve.
(12)(18)(32.5)=(25)(12)x
Divide both sides by 12
(18)(32.5)=25x
Solve left side
585=25x
Divide by 25
x=23.4
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Step-by-step explanation:

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Step-by-step explanation:

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On a balance of $1448.00, calculate this month's finance charge @ 1.75%/month
Alex787 [66]
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4 years ago
The German autobahns are the nationally coordinated motorway system in Germany and have no general speed limit, but the advisory
melamori03 [73]

Answer:

The required equation is: s=0.0508v^2

The stopping distance of your car if you were moving at 95 mph is 458.47 feet.

Step-by-step explanation:

Consider the provided information.

Part (A)

Let us consider "s" is the distance  "v" is the velocity and "k" is the constant of variation.

It is given that the stopping distance of a car varies directly as the square of the velocity of car when the brakes are applied

This can be written as:

s=kv^2 ......(1)

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Substitute v=85 and s=367 in above formula and solve for k.

367=k(85)^2

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Now to find the equation that relates the stopping distance to the velocity substitute the value of k in equation 1.

s=0.0508v^2

Hence, the required equation is: s=0.0508v^2

Part (B)

Calculate the stopping distance of your car if you were moving at 95 mph.

Substitute the value of v=95 in s=0.0508v^2

s=0.0508(95)^2

s=0.0508\times 9025

s=458.47

Hence, the stopping distance of your car if you were moving at 95 mph is 458.47 feet.

4 0
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5 0
3 years ago
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