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Blizzard [7]
3 years ago
14

Which length measurement is the most precise?

Mathematics
1 answer:
Alex777 [14]3 years ago
3 0
I believe the answer is B. 24.36 Centimeters.
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Need help SOON please. I'll be forever grateful. <br> see attached image!
vichka [17]
Ok i cant answer the exact answer cause i don’t have paper put i’ll give you the format
it’s is
y2-y1
———-
x2-x1

that’s is the formula, you take the second y coordinate and subtract it from the first y then you do the second x coordinate and subtract it from the first x coordinate. hope this helps you
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CaHeK987 [17]

the heck (keystrokes keystrokes)

6 0
3 years ago
Which would you measure using yards?
igomit [66]
Width of a watch can be measured in cms or inches, since it's too small. Distance to the moon is measured in light years, since  it is too large. Length of your finger is measures  in cms or inches, since it is too small. The length if a roller skating ring is rightly measured in yards, since it is just the right size. It can also be measured in feet.
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3 years ago
Read 2 more answers
E Homework: 3.1 Homework
LenKa [72]

The given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

The given function is f(z)=3z-8.

We need to find the value of f(-4), f(2), f(z-7).

<h3>What is a function?</h3>

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

Now to find f(-4), replace z from -4.

f(-4)=3(-4)-8=-12-8=-20

Now to find f(2), replace z from 2.

f(2)=3(2)-8=6-8=-2

Now to find f(z-7), replace z from z-7.

f(z-7)=3(z-7)-8=3z-21-8=3z-29.

Therefore, the given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.

To learn more about functions visit:

brainly.com/question/21145944.

#SPJ1

4 0
2 years ago
1.
RUDIKE [14]

Answer:

Answer:

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

m=

m=

=3

Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

v = -12 cm

m = 12/20 = 0.6

size of final image = .6 x 30 = 18 cm

3 0
4 years ago
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