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statuscvo [17]
3 years ago
15

CANNNN SOMEONEEEEE HELPPPP MEEE OUTTTTT !!!!!

Mathematics
2 answers:
oee [108]3 years ago
5 0

Answer:

\boxed{\sf sinX =\frac{21}{29}}

Step-by-step explanation:

We need to find out the value of sinX using the given triangle . Here we can see that the sides of the triangle are 21 , 29 and 20.

We know that the ratio of sine is perpendicular to hypontenuse .

\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}

Here we can see that the side opposite to angle X is 21 , therefore the perpendicular of the triangle is 21. And the side opposite to 90° angle is 29 . So it's the hypontenuse . On using the ratio of sine ,

\sf\longrightarrow sinX =\dfrac{ p}{h}=\dfrac{ZY}{ZX}

Substitute the respective values ,

\sf\longrightarrow \boxed{\blue{\sf sin\ X =\dfrac{21}{29}}}

<u>Hence</u><u> the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>1</u><u>/</u><u>2</u><u>9</u><u> </u><u>.</u>

USPshnik [31]3 years ago
3 0

Answer:

sin X = 21/ 29

Step-by-step explanation:

Since this is a right triangle

sin X = opp side/ hypotenuse

sin X = 21/ 29

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