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ioda
3 years ago
10

How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2? Set

1: 82, 80, 90 Set 2: 82, 80, 60, 90 The MAD of set 1 is 6 less than the MAD of set 2. The MAD of set 1 is 5 less than the MAD of set 2. The MAD of set 1 is 5 more than the MAD of set 2. The MAD of set 1 is 6 more than the MAD of set 2.
Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

Set 1: 4

Set 2: 9

The MAD of set 1 is 5 less than the MAD of set 2.

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Step-by-step explanation:

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Perform the indicated operation:
yaroslaw [1]

The expression \frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} } is equal to \frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3}.

<h3>How to simplify a composite algebraic expression</h3>

In this question we must use properties of <em>real</em> algebra to simplify a given expression as most as possible. We proceed to show each step with respective reason.

  1. \frac{m^{2}-16\cdot n^{2}}{\frac{3\cdot m + 12\cdot n}{m\cdot n} }  Given
  2. \frac{m\cdot n \cdot (m^{2}-16\cdot n^{2})}{3\cdot m + 12\cdot n}   \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{c\cdot b}
  3. \frac{m\cdot n \cdot (m-4\cdot n)\cdot (m+4\cdot n)}{3\cdot (m+4\cdot n)} Distributive property/a^{2}-b^{2} = (a +b)\cdot (a-b)
  4. \frac{m\cdot n \cdot (m-4\cdot n)}{3} Existence of the multiplicative inverse/Modulative property
  5. \frac{m^{2}\cdot n}{3} -\frac{4\cdot m\cdot n^{2}}{3} Distributive property/x^a\cdot x^{b} = x^{a+b}/Result

To learn more on algebraic expressions, we kindly invite to check this verified question: brainly.com/question/953809

7 0
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ICE Princess25 [194]

Answer:x=7

Step-by-step explanation:

X+3=10

-3 -3

X=7

5 0
4 years ago
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Look at the image below plzz urgant help !!!!!! NEED DONE IN TEN MINUTES
daser333 [38]

Answer:

V≈113.1

Step-by-step explanation:

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3=π·32·12

3≈113.09734

5 0
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