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ioda
3 years ago
10

How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2? Set

1: 82, 80, 90 Set 2: 82, 80, 60, 90 The MAD of set 1 is 6 less than the MAD of set 2. The MAD of set 1 is 5 less than the MAD of set 2. The MAD of set 1 is 5 more than the MAD of set 2. The MAD of set 1 is 6 more than the MAD of set 2.
Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

Set 1: 4

Set 2: 9

The MAD of set 1 is 5 less than the MAD of set 2.

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Evaluate the expression for the given variable. Show all work to earn credit 2x2 + 3y +6 if x = 2 and y = 9?
Sladkaya [172]

Answer:

41

Step-by-step explanation:

4 0
3 years ago
Adele opens an account with $100 and deposits $35 a month. Kent opens an account with $50 and also deposits $35 a month. Will th
suter [353]
They will not ever have the same amount because Adele is most likely $50 ahead of Kent each time.
6 0
3 years ago
Quadrilateral KLMN is a rectangle. The coordinates of L are L(1,-4), and the coordinates of Mare M(3,-2). Find the slopes of sid
lozanna [386]
L(1, -4)=(xL, yL)→xL=1, yL=-4
M(3, -2)=(xM, yM)→xM=3, yM=-2

Slope of side LM: m LM = (yM-yL) / (xM-xL)
m LM = ( -2 - (-4) ) / (3-1)
m LM = ( -2+4) / (2)
m LM = (2) / (2)
m LM = 1

The quadrilateral is the rectangle KLMN
The oposite sides are: LM with NK, and KL with NK
In a rectangle the opposite sides are parallel, and parallel lines have the same slope, then:
Slope of side LM = m LM = 1 = m NK = Slope of side NK
Slope of side NK = m NK = 1

Slope of side KL = m KL = m MN = Slope of side MN

The sides KL and LM (consecutive sides) are perpendicular (form an angle of 90°), then the product of their slopes is equal to -1:
(m KL) (m LM) = -1
Replacing m LM = 1
(m KL) (1) = -1
m KL = -1 = m MN

Answer:
Slope of side LM =1
Slope of side NK =1
Slope of side KL = -1
Slope of side MN = -1 
3 0
3 years ago
X^2 - 9x -10 =0 has a discriminant of: a. 121 b. 72 c. -359 d. 41 e. 136
Feliz [49]
In the standard form of quadratic
ax^{2} +bx+c
the discriminant is
b^{2} -4ac
In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.
7 0
2 years ago
What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11
Scrat [10]

Try 122.

<h3 />

Step-by-step explanation:

Since <em>x</em> = 1, x^6 = 1.

Since <em>y</em> = 11, 11^2 = 121.

1 + 121 = 122.

<h3 /><h3>So, the value of <em>x</em> ^ 6 + <em>y </em>^ 2 = 122.</h3><h3 />
8 0
2 years ago
Read 2 more answers
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