All categories

3 years ago

What is the value of x

Mathematics

1 answer:

aivan3 [116]3 years ago

8 0

The original value of x was negative, then –x, the opposite-signed version of x, would have to be positive. For instance, if I start with x = –3, then –x = –(–3) = +3, which is positive.

You might be interested in

how many solutions does the equation 2(2x- 10)-8 =-2(14-3x) have?A.exactly one solution B. exactly two solutions C. no solution

Zarrin [17]

Answer: it has no solutions

Step-by-step explanation:

Factor then solve to find the complex solutions.

5 0

2 years ago

Answer ASAP pls pls answer

Harrizon [31]

Answer:

Figures with the same size and shape are congruent.

5 0

3 years ago

Read 2 more answers

20 points

kodGreya [7K]

Answer:

a) x=0, x=-10, x=11

Step-by-step explanation:

Just find the x- coordinates for when f(x) intersects g(x).

5 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

How do I do linear equations using the elimination method

nexus9112 [7]

In order to use the elimination method, you have to create variables that have the same coefficient—then you can eliminate them. Multiply the top equation by 5. Next add the equations, and solve for y. Substitute y = 10 into one of the original equations to find x.

8 0

3 years ago