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Alja [10]
3 years ago
14

Daddy needs to make 16 costumes for the school play.Each costume requires 2 1/4 yards of material. How many yards of material wi

ll he need
Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

7 costumes

I found this by dividing the two numbers and when divided the answer is 7 and 1/9 but you cant have 1/9th of a costume so it would only be 7

Hope this helps

If any questions leave a comment

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The sum of thrice a number and 5 is greater than or equal to the sum of twice a number and 1. Write down the inequality and solv
sertanlavr [38]

Answer:

May be helpful.

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7 0
1 year ago
Brainliest question Please help me now plz
V125BC [204]
Side a = 10.98991
Side b = 11.69522
Side c = 4

Angle ∠A = 70° = 1.22173 rad = 7/18π
Angle ∠B = 90° = 1.5708 rad = π/2
Angle ∠C = 20° = 0.34907 rad = π/9


6 0
3 years ago
Which model is NOT a function? (i accidentally clicked on b ignore that lol)
olga_2 [115]

Answer:

C

Step-by-step explanation:

It's the only one where an x-axis has more than one y-axis.

I hope this explanation helps.

8 0
3 years ago
A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes
Elena L [17]

Answer:

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

\hat p=\frac{282}{830}=0.340 estimated proportion of people that regularly watch the TV station’s news program

p_o=0.38 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:  

Null hypothesis:p\geq 0.38  

Alternative hypothesis:p < 0.38  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

3 0
3 years ago
HELP ASAP PLEASE <br> Not understanding and need answers asap
Neko [114]

Answer:

you domb if you dont know the answer B

Step-by-step explanation:

7 0
2 years ago
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