To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
I think I may be wrong check
5(x^2n-1)×(2x^3n-1) ^2
=20n3 x8 -20n2 x5 +20n x3 +20n x3 +5n x2-5
The <u>rise</u> is the difference in y-coordinates:
The <u>run</u> is the difference in x-coordinates:
The <u>slope</u> is the quotient of rise over run:
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If two points on a line are A(10, −3) and B(12, 9), the rise is <u>12</u>, and the run is <u>2</u>, so the slope of the line is <u>6</u>.
Answer:
the answer is 24.1 MM
Step-by-step explanation:
