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3 years ago

SOMEONE HELP ME PLSSSSSSSSSSSSSS

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

3 0

The third angle is 48 degrees. The second part, I think should be b < a < c because you can go across from the angles shortest to largest.

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Which of the following triangles have three sides of different length? A. acute B. scalene C.equilateral D. right

katen-ka-za [31]

Answer:

scalene

hope this helps

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Step-by-step explanation:

4 0

3 years ago

PLZ HURRY IT'S URGENT!!

Dahasolnce [82]

Answer:

1/2.

Step-by-step explanation:

10m = 5n

m = 5n/10

m = n/2

m/n = n/2 * 1/n

m/n = 1/2.

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3 years ago

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What is the value of y when x = 3. y = 12x

alexandr1967 [171]

We have the equation y = 12x. And we know the value of x. The value of x is 3.
So, if we replace the x variable with the value of x, then we can solve the equation.

y = 12(3)
y = 36

So, the answer is 36.

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3 years ago

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A random sample of 64 second-graders in a certain school district are given a standardized mathematics skills test. The sample m

svet-max [94.6K]

Answer:

Given : The sample mean score is 51.48 .

The standard deviation for the population of test scores is 15.

The nationwide average score on this test is 50.

To Find : Perform the hypothesis test and compute the P-value?

Solution:

Sample size = n = 64

Since n > 30

So, we will use z test over here

We are supposed to find The school superintendent wants to know whether the second-graders in her school district have greater math skills than the nationwide average.

Hypothesis : $H_0:\mu \leq 50\\H_a:\mu>50$

Formula of z test : $z =\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$x = 51.48\\\mu = 50\\\sigma = 15\\ n = 64$

Substitute the values

$z =\frac{51.48-50}{\frac{15}{\sqrt{64}}}$

$z =0.789$

Find the value of P(z) from z table

p(z)=0.7823

Since we are given that we are supposed to find The school superintendent wants to know whether the second-graders in her school district have greater math skills than the nationwide average.

So, p value = 1-P(z) = 1-0.7823=0.2177

In general , Level of significance is 0.05

So, p value is greater than alpha.

So, we accept the null hypothesis.

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3 years ago

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Semenov [28]