3 years ago

Without expanding show that. Help please!

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

3 0

Answer:
I’m sorry but I can’t answer until you explain

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Noah and Lin are each trying to solve the equation x² - 6x + 10 = 0. They know that the solutions to x² = - 1 are i and -i, but

Leviafan [203]

Answer:

Solving the equation $x^2 - 6x + 10 = 0$ we get $x=3+i \ , \ x=3-i$

Step-by-step explanation:

Noah's step to solve the equation $x^2 - 6x + 10 = 0$ are:

$x^2 - 6x + 10 = 0\\x^2 - 6x = -10\\x^2 - 6x + 9 = -10 + 9\\(x-3)^2 = -1$

The next step is to take square root on both sides because: $\sqrt{x^2}=x$

$\sqrt{(x-3)^2}=\sqrt{-1} \\x-3=\pm\sqrt{-1} \\x=\pm(\sqrt{-1})+3 \\$

Now, we know that: $\sqrt{-1}=i$

$x=\pm(i)+3\\x=3+i \ , \ x=3-i$

So, Solving the equation $x^2 - 6x + 10 = 0$ we get $x=3+i \ , \ x=3-i$

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3 years ago

If t=0 in 1980, find the value of A. Round answer to the nearest million.

balu736 [363]

P=Ae^kt

225 = 210 * e^(k*(1990-1980)

225/210=e^10k ln(225/210)=10k

k=ln(225/210)/10=0.0069

P = 210*e^(0.0069t)

for 2000 ===> t = 2000-1980=20

P = 210*e^(0.0069*20)

P=241.0749=241

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4 years ago

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Lapatulllka [165]

I dont completely know but it might be 3

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3 years ago

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Answer: Eighty-seven thousand-fifty five

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3 years ago

Without expanding show that. Help please!​

Without expanding show that. Help please!