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blsea [12.9K]
3 years ago
9

if i wanted to make a 40,000 payment in one year with a 5% annual interest rate, how much should i invest now?

Mathematics
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

38,095.24

Step-by-step explanation:

40,000 = P(1 + 0.05)^1

P = 40,000/1.05

P = 38095.2380952

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Which graph represents the function h(x) = -(x + 6)3 - 3?
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Step-by-step explanation:

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3 years ago
Mr. Smith has 12 congruent boxes shaped like rectangular prisms in his office. If the length is 25 inches, the height is 2 feet,
Nana76 [90]

Answer:

width of one box = 1.25 inches

Step-by-step explanation:

Given data:

12 congruent boxes

Length = 25 inches

height = 2 feet

Volume = 9000 cubic inches

First change the height into inches

1 foot = 12 inches

therefore 2 feet = 24 inches

Volume = Length * width * height

9000 = 25 * width * 24

9000 = 600 * width

width = 9000/600

width = 15 inches

width of one box = width of all boxes / number of boxes

width of one box = 15/12

width of one box = 1.25 inches

4 0
3 years ago
The table shows a linear function. x -5,-4,-3,-2,-1, 0, 1, 2, 3. on top row f(x) -11, -3, 5, 13, 21, 29, 37, 45, 53. on bottom r
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Which one of these is the easiest to obtain energy from?:<br><br> a candle<br> a lamp
torisob [31]
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8 0
2 years ago
A small regional carrier accepted 16 reservations for a particular flight with 12 seats. 8 reservations went to regular customer
wolverine [178]

Answer:

a) 32.04% probability that overbooking occurs.

b) 40.79% probability that the flight has empty seats.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a passenger arriving is independent of other passengers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Our variable of interest are the 8 reservations that went for the passengers with a 48% probability of arriving.

This means that n = 8, p = 0.48

A) Find the probability that overbooking occurs.

12 seats, 8 of which are already occupied. So overbooking occurs if more than 4 of the reservated arrive.

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{8,5}.(0.48)^{5}.(0.52)^{3} = 0.2006

P(X = 6) = C_{8,6}.(0.48)^{6}.(0.52)^{2} = 0.0926

P(X = 7) = C_{8,7}.(0.48)^{7}.(0.52)^{7} = 0.0244

P(X = 8) = C_{8,5}.(0.48)^{8}.(0.52)^{0} = 0.0028

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2006 + 0.0926 + 0.0244 + 0.0028 = 0.3204

32.04% probability that overbooking occurs.

B) Find the probability that the flight has empty seats.

Less than 4 of the booked passengers arrive.

To make it easier, i will use

P(X < 4) = 1 - (P(X = 4) + P(X > 4))

From a), P(X > 4) = 0.3204

P(X = 4) = C_{8,4}.(0.48)^{4}.(0.52)^{4} = 0.2717

P(X < 4) = 1 - (P(X = 4) + P(X > 4)) = 1 - (0.2717 + 0.3204) = 1 - 0.5921 = 0.4079

40.79% probability that the flight has empty seats.

4 0
3 years ago
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