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3 years ago

if i wanted to make a 40,000 payment in one year with a 5% annual interest rate, how much should i invest now?

Mathematics

1 answer:

IRINA_888 [86]3 years ago

5 0

Answer:

38,095.24

Step-by-step explanation:

40,000 = P(1 + 0.05)^1

P = 40,000/1.05

P = 38095.2380952

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The answer is C that’s why it has a 1 pt in front <br><br> Plz just help me explain how to get that

Ierofanga [76]

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3 years ago

NEED HELP ASAP 30 POINTS

klemol [59]

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2 years ago

(NEED HELP ASAP!!!) Jamie unfolded a cardboard box. The figure of the unfolded box is shown below: A long rectangle divided alon

Oksanka [162]

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Step-by-step explanation:

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3 years ago

An airplane has 29 seats. The price for a coach seat is $600 in the price for a first class seat is $1050. The airline collected

In-s [12.5K]

Answer:

19 coach seats

Step-by-step explanation:

let the number of coach seats be C and number of first class seats be F

given that the total number of seats is 29,

C + F = 29 ---------(eq 1)

also given that each coach seat = $600, each 1st class seat is $1050 and a total of $21900 was collected,

600C + 1,050F = 21,900 -------(eq 2)

we have 2 equations and 2 unknowns, we can solve the system of equations by elimination

(eq 1) x 1,050 gives us:

1,050 (C + F) = 1,050(29)

1,050C + 1,050F = 30,450 ----- (eq 3)

by elimination, subtract eq 2 from eq 3

(1,050C + 1,050F) - (600C + 1,050F) = 30,450 - 21,900

1,050C - 600C = 8,550

450C = 8550

C = 855 /450

C = 19

7 0

3 years ago

Explain why S = {(5, 4, -2), (-15, -12, 6), (10, 8, -4)} is NOT a basis for R^3 (1 point Sis linearly dependent and spans R3 S i

earnstyle [38]

$S$ would be a basis for $\mathbb R^3$ if

(1) the vectors in $S$ are independent, and

(2) the vectors span $\mathbb R^3$ .

Linear independence requires that $c_1=c_2=c_3=0$ is the only solution to

$c_1(5,4,-2)+c_2(-15,-12,6)+c_3(10,8,-4)=(0,0,0)$

These vectors are not linearly independent because if $c_1=3$ , $c_2=1$ , and $c_3=0$ , we have

$3(5,4,-2)+(-15,-12,6)=(15-15,12-12,-6+6)=(0,0,0)$

so $S$ is not a basis for $\mathbb R^3$ .

7 0

3 years ago