Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.
<h3>What centers of distribution should be used?</h3>
The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.
The data is said to be symmetric when the mean and median are equal or very close.
Bakery A mean:
= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8
= 49
Bakery A median is 49.5
Bakery B mean:
= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8
= 39.5
Bakery B median is 44.
This shows that Bakery A data is symmetric so the best center of distribution to use is mean.
Bakery B is not symmetric so the center of distribution to use is median.
Find out more on symmetric data at brainly.com/question/7130507
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#2 #3 and #5 I think but I could be wrong. Good luck!
To find the 7th term, all you have to do is plug it in the equation.
First n would equal 7 because we are looking for the 7th term.
Now, let's plug everything we know into the equation.
a7 = 2+5 * (7-1)
= 2 + 5 * 6
= 2 + 30
= 32
In conclusion, the 7th term would equal 32.
Answer:
Step-by-step explanation:
we know that
The equation of the line into slope intercept form is equal to
where
m is the slope
b is the y-intercept
we have
----> equation of the line into point slope form
Convert to slope intercept form
Isolate the variable y
Distributed left side
subtract 5 both sides
