Question

What’s the equation of a circle with a center -3,4 and radius 1

Answer 1

Answer:

$(x+3)^2 + (y-4)^2 = 1$

Step-by-step explanation:

Equation of a circle can be found by

$(x-a)^2 + (y-b)^2 = r^2$

Given center 3,-4 i.e

a= 3 and b=-4

and radius r = 1

Putting the values of a,b and r in the equation we get:

$(x-(-3))^2 + (y-4)^2 =(1)^2\\(x+3)^2 + (y-4)^2 = 1$