At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
Answer:

Step-by-step explanation:
step 1
Find the length side PQ
we know that
The area of rectangle PQRS is given by


so

substitute the value of QR

solve for PQ

step 2
Find the length side AB
we know that
The perimeter of rectangle ABCD is given by

we have

substitute

solve for AB

Answer: Cost of tickets for adults = $22
Cost of tickets for children = $15
Total number of tickets sold = 732
Total receipts = $12,912
Let x be number of adult ticket's sold and y be the number of child ticket's sold.
Therefore, we have:
--------------- equation 1

Also, we have:

Now, let's substitute the value of x:






Now, let's substitute the value of y=456 in equation 1, we have:



Therefore, the number of child ticket's sold is 456 and number of adult ticket's sold is 276
Answer: (-1,2) and (2,2) Make sure to see explanation!
Step-by-step explanation:
Well you need to remember the Y reflection rule!
To reflect over the Y axis you must do this:
Take the points in this case
(1,2) and (-2,2)
And you need to use the equation (x,y) --> (-x,y)
So the new points you NEED TO GRAPH ARE
(-1,2) and (2,2)
Hope this helped!