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lisabon 2012 [21]
3 years ago
8

PLEASE HELP! ASAP! URGENT!

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

g(-7)= -37

Step-by-step explanation:

g(y)= 7y + 12

plug in -7

g(-7)= 7(-7) + 12

simplify

g(-7)= -49 +12

g(-7)= -37

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Answer:

I believe the A goes with the B the B goes with D that al I know soryy

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PLEASE HELP FAST!!! The greatest common factor of 56f^3 g^2 and 70fg^3 is 7fg^3. True or False
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7 0
4 years ago
Given: an n-gon Prove: The sum of the measures of the interior angles is 180(n – 2)°. Complete the missing parts of the paragrap
icang [17]

Given: an n-gon

Prove: The sum of the measures of the interior angles is 180(n – 2)°.

Complete the missing parts of the paragraph proof.

We are given an n-gon, which has n sides and n vertices.

Answers:

1. If we choose one of the vertices, we can draw <u>n-3</u> diagonals.

2. These diagonals form <u>n-2</u> triangles.

3. The sum of the interior angle measures of a triangle is <u>180</u> degrees.

4. <u>n – 2</u> triangles would have an interior angle measure sum of <u>180</u> degrees.

5. Therefore, the sum of the measures of the interior angles of an n-gon is 180(n – 2)°.

5 0
3 years ago
Read 2 more answers
HELP NEEDED ASAP. "ONLY ANSWER IF YOU KNOW THE ANSWER"
valkas [14]

Answer:

x =-5±  2i sqrt(14)

Step-by-step explanation:

x^2 + 10x= -81

Take the coefficient of x and divide by 2

10/2 = 5

Square it

5^2 =25

add to each side

x^2 + 10x+25 = -81+25

( x+5) ^2 = -56

Take the square root of each side

sqrt(( x+5) ^2) =± sqrt(-56)

x+5 = ± sqrt(-1) sqrt(4*14)

x+5 =± i sqrt(4)sqrt(14)

x+5 =± i 2 sqrt(14)

Subtract 5 from each side

x+5-5 =-5± i 2 sqrt(14)

x =-5±  2i sqrt(14)

4 0
3 years ago
50 points! Show your work!
Evgesh-ka [11]

Answer:

a)19.28≈x (rounded to the nearest hundredth)

b)7.66≈x (rounded to the nearest hundredth)

c)x≈8.39(rounded to the nearest hundredth)

d)x≈36.87 (rounded to the nearest hundredth) and y=5

Step-by-step explanation:

I'm going to first assume that all of these are right triangles.

If you look at the hint, it says SOHCAHTOA

This stands for the trigonometric functions

SOH tells us that sine(θ)=opposite/hypotenuse

CAH tells us that cosine(θ)=adjacent/hypotenuse

TOA tells us that tangent(θ)=opposite/adjacent

(ps. θ, or theta, stands for any angle measure)

Now, let's look at problem a.

We have the value of the hypotenuse and the value of an angle. We want to find the side opposite from the angle. So, in this case, we want to use the sine function.

sin(40)=x/30

30*sin(40)=x

19.28≈x (rounded to the nearest hundredth)

We can solve the other problems in a similar fashion.

Problem b

We have the hypotenuse, an angle measure, and we want to find the adjacent side. This is telling us to use the cosine function.

cos(40)=x/10

10*cos(40)=x

7.66≈x (rounded to the nearest hundredth)

Problem c

We have an angle measure, an adjacent value, and we want to find the opposite length, so we're going to use the tangent function.

tan(40)=x/10

10*tan(40)=x

x≈8.39(rounded to the nearest hundredth)

Problem d

We need to first solve for x, the angle measure.

We have an opposite length, an adjacent length, so we can use the tangent function to solve for the missing angle

Let's set up an equation

tan(x)=3/4

Using tan^{-1} or tangent inverse to cancel out the tangent, we get

x=tan^{-1}(3/4)

x≈36.87 (rounded to the nearest hundredth)

Now, let's solve for y, the hypotenuse!

Both the sine and cosine functions work, so I'm just going to pick one.

sine(36.87)=3/y

y*sin(36.87)=3

y=3/sin(36.87)

y=5

Side note: Although I rounded the angle measure, when calculating the y value, on my calculator, I did not round the value. Don't round until the end on your calculator, but it's okay to round on your paper.

PS. I used degrees for the angle measures, not radians, so if you want to retry these problems, make sure your calculator is calculating degrees, not radians, or else you might get some funky answers.

6 0
3 years ago
Read 2 more answers
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