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3 years ago

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In June, you bought 14.5 gallons of gasoline for $3.18 per gallon. The following February, you bought the same amount of gasolin

e for $1.88 per
gallon. Select the expression(s) that you can use to find how much more you paid in June than in February. Then find this amount
14.5 (3.18 - 1.88)
14.5 x 1.88 - 14.5 x 3.18
14.5 x 3.18 - 14.5 x 1.88
14.5 x 1.88 +14.5 x 3.18
You paid $
more in June than in February???

1 answer:

Nata [24]3 years ago

3 0

Answer:

14.5 × 3.18 - 14.5 x 1.88

You paid $18.85 more in june than in February

Step-by-step explanation:

In order to find the answer to this question you will need to find how much you paid in June and how much you paid in February.

ex.14.5 x 3.18 - 14.5 x 1.88

To solve this you need to find the product of 14.5 x 3.18 and 14.5 x 1.88 and then subtract them from eachother.

ex.14.5 x 3.18 =46.11

14.5 x 1.88=27.26

46.11-27.26=18.85

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<u />

<u>(a) Probability that a person is sick</u>

From the table, we have:

$\mathbf{Sick = 59+1 = 60}$

So, the probability that a person is sick is:

$\mathbf{Pr = \frac{Sick}{Total}}$

This gives

$\mathbf{Pr = \frac{60}{7500}}$

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<u>(b) Probability that a test is positive, given that the person is sick</u>

From the table, we have:

$\mathbf{Positive\ and\ Sick=59}$

So, the probability that a test is positive, given that the person is sick is:

$\mathbf{Pr = \frac{Positive\ and\ Sick}{Sick}}$

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The probability that a test is positive, given that the person is sick is 0.9833

<u>(c) Probability that a test is negative, given that the person is not sick</u>

From the table, we have:

$\mathbf{Negative\ and\ Not\ Sick=7365}$

$\mathbf{Not\ Sick = 75 + 7365 = 7440}$

So, the probability that a test is negative, given that the person is not sick is:

$\mathbf{Pr = \frac{Negative\ and\ Not\ Sick}{Not\ Sick}}$

This gives

$\mathbf{Pr = \frac{7365}{7440}}$

$\mathbf{Pr = 0.9899}$

The probability that a test is negative, given that the person is not sick is: 0.9899

<u>(d) Probability that a person is sick, given that the test is positive</u>

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$\mathbf{Positive\ and\ Sick=59}$

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So, the probability that a person is sick, given that the test is positive is:

$\mathbf{Pr = \frac{Positive\ and\ Sick}{Positive}}$

This gives

$\mathbf{Pr = \frac{59}{134}}$

$\mathbf{Pr = 0.4403}$

The probability that a person is sick, given that the test is positive is: 0.4403

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$\mathbf{Negative\ and\ Not\ Sick=7365}$

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$\mathbf{Pr = \frac{Negative\ and\ Not\ Sick}{Negative}}$

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$\mathbf{Pr = \frac{7365}{7366}}$

$\mathbf{Pr = 0.9998}$

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