65+55x <=200 solve the inequality

Mathematics

2 answers:

fomenos2 years ago

7 0

Answer:

Step-by-step explanation:

55x<=200-65

55x<=135

x<=135\55

x<=2.46

Y_Kistochka [10]2 years ago

3 0

X is less than or equal to 27/11

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Amount Financed (m) = $1,860 Number of Payments per year (y) = 12 Number of Payments (n) = 36 Total Interest (c) = $350.00

Luda [366]

Hi there
The formula to find I (ARP)

I=(2yc)/(m×(1+n)
I=(2×12×350)÷(1,860×(1+36))
I=0.1221×100
I=12.21%

Good luck!

8 0

2 years ago

Plz help me with this

Nat2105 [25]

The total number of inches is 20.36.
All you have to do is add up all the sides and you will get your answer.

5.36+8.8+4.62+1.58= 20.36
Hope this helps!!! :D

7 0

3 years ago

Read 2 more answers

Solve the following equations by factorisation method.Only factorisation not dharacharya.

Luba_88 [7]

Hello, please consider the following.

When $x_1$ and $x_2$ are two roots, we can factorise as

$ax^2+bx+c=a(x-x_1)(x-x_2)=a(x^2-(x_1+x_2)x+x_1x_2)=0$

So for the first equation, we can say that the sum of the zeros is

$\dfrac{a^2+b^2}{2}=\dfrac{a^2}{2}+\dfrac{b^2}{2}$

and the product is

$\dfrac{a^2b^2}{4}=\dfrac{a^2}{2}\dfrac{b^2}{2}$

So we can factorise as below.

$4x^2-2(a^2+b^2)x+a^2b^2=(2x-a^2)(2x-b^2)=0$

And the solutions are

$\boxed{\sf \n\bf \ \dfrac{a^2}{2} \ \ and \ \ \dfrac{b^2}{2}}$

For the second equation, we will complete the square and put the constant on the right side and take the root.

Let's do it!

$9x^2-9(a+b)x+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2-9\dfrac{(a+b)^2}{4}+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9(a+b)^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9a^2+18ab+9b^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{a^2+b^2-2ab}{4}=\dfrac{(a-b)^2}{4}\\\\(x-\dfrac{a+b}{2})^2=\dfrac{(a-b)^2}{2^2\cdot 3^2}$