<span> the population grows at rate of 1.75
multiply it by this rate every year
As in year 3 it would be 5340(1.75)(1.75)(1.75)
the function is 5340(1.75)^x
</span>f(x) = 5340(1.75)^x where 1.75 is the rate of growth
so D is right answer
1. (7 − 3i) • (2 − i)
It is simplified as follows:
14 - 7i -6i - 3
11 - 13i
2. <span>(−5 + 3i) • (1 − 2i)
</span><span>It is simplified as follows:
</span><span>-5 + 10i + 3i + 6
1 + 13i
3. (1 + 3i) + (2 − 5i)
</span><span>It is simplified as follows:
</span>1 + 3i + 2 − 5i<span>
3 - 2i
4. (6 + 2i) − (8 − 3i)
</span><span>It is simplified as follows:
</span><span>6 + 2i − 8 + 3i
</span>-2 + 5i
Answer: first option 3, - 7
Justification:
1) Given expression:9x² - 5x - 7
2) Each monomial is a term.
The monomials are each combination of numbers and letters (coefficient, letters and exponents) separated of other monomials (terms) with a + or - operator.
3) Therefore, there are 3 terms which are:
9x²,
-5x, and
-7.
The polynomials with 3 terms are called monomials.
4) The monomial (term) withoud letter is the constant. In this case that is -7.
Answer: 31 : 9
Step-by-step explanation:
Assume the following:
Alice's amount = P
Bob's amount = Q
Amount received = n
If Alice receives $n$ dollars from Bob ;then she will have $4$ times as much money as Bob.
P + n = 4(Q - n)
P + n = 4Q - 4n
P = 4Q - 4n - n
P = 4Q - 5n - - - - (1)
If, on the other hand, she gives $n$ dollars to Bob, then she will have $3$ times as much money as Bob
P - n = 3(Q + n)
P - n = 3Q + 3n
P = 3Q + 3n + n
P = 3Q + 4n - - - - - - (2)
Equating both equations - (1) and (2)
4Q - 5n = 3Q + 4n
4Q - 3Q = 4n + 5n
Q = 9n
Express P in terms of n, use either equation (1) or (2)
From equation 2:
P = 3Q + 4n
Substituting Q = 9n
P = 3(9n) + 4n
P = 27n + 4n
P = 31n
Alice's amount = P, Bob's = Q
Ratio = P:Q
31 : 9
The first thing you want to do is plug in x and y into both equations:
a(3) + b(4) = 4
b(3) + a(4) = 8
rearrange to line up a’s and b’s
3a + 4b = 4
4a + 3b = 8
now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.
4(3a + 4b = 4) = 12a + 16b = 16
3(4a + 3b = 8) = 12a + 9b = 24
Now we subtract the bottom equation from the top and solve for b:
12a + 16b - (12a + 9b) = 16 - 24
7b = -8
b = -8/7
Now we plug back in for b to one of the original equations:
3a + 4(-8/7) = 4
3a + (-32/7) = 4
3a - (32/7) = 4
3a = 4 + (32/7)
3a = (28/7) + (32/7)
3a = 60/7
a = (60/7)/3 = 20/7.
Finally, plug a and b in together to double check using the second equation.
4a + 3b = 8
4(20/7) + 3(-8/7) = ?
(80/7) - (24/7) = ?
56/7 = 8.
