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Inessa05 [86]
3 years ago
9

Wiil mark bianleast

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer:

7 units to the right and 2 units up

Step-by-step explanation:

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The temperature was 14`°F`. If the temperature dropped 5 degrees every hour for 4 hours, what is the temperature after the 4 hou
Nina [5.8K]

Answer:

-6F

Step-by-step explanation: It would be 5F(4hr) = 20F. So if you have 14F subtract 20F you get -6F. Hope this helped.

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2 years ago
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zhannawk [14.2K]
The domain is the range of the x-axis. In this situation the x range from 0 to 11, so the domain is D.
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2 years ago
TIME REMAINING
alekssr [168]

The solution of the equations is (-2, -1)

<h3>System of equation:</h3>

2x - 3y = -1

11x  - 9y = -13

Using elimination method let multiply the first equation by -3.

Therefore,

-6x + 9y = 3

11x - 9y = -13

5x = -10

x = -10 / 5

x = -2

let's find y as follows;

2(-2) - 3y = -1

-4 - 3y = -1

-3y = -1 + 4

-3y = 3

y = 3 / -3

y = -1

learn more on system of equation here: brainly.com/question/1451150

6 0
2 years ago
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2 years ago
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An object is placed 21 cm from a concave lens of focal length 25 cm. what is the magnification?
wariber [46]

The magnification is 0.54

Given,

The distance between object and concave lens, u = -21 cm

Focal length of the concave lens, f = -25 cm

Let m be the magnification.

m = v/u

Here v is the position of image.

We have to find v first.

By using lens equation we can determine v.

That is,

1/f = 1/v – 1/u

So,

- (1/25) = 1/v – (-1/21)

- (1/25) = 1/v + 1/21

1/v = - (1/25) – 1/21

1/v = (-25 – 21) / (21 x 25)

1/v = - (46/525)

Therefore v = - (525/46)

   v = -11.41 cm

Now we have to find magnification, m.

m = v/u

   = (-11.41) / (-21)

   = 0.54

Here magnification is 0.54

Learn more about concave lens here: brainly.com/question/12944945

#SPJ4

6 0
2 years ago
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