Question

Triangle ABC is translated on the coordinate plane below to create triangle A'B'C':

Answer 1

the answer for this case is
 since the translation is
 b. (4, 9)
 (x + 3, y + 6)
 for each ordered pair

Answer 2

Answer:  The correct option is (b) (4, 9).

Step-by-step explanation:  Given that the triangle ABC is translated on the coordinate plane shown to create triangle A'B'C'.

And the parallelogram EFGH is translated according to the same rule that translated triangle ABC.

We are to find the ordered pair of the point H'.

From the figure, we note that

the co-ordinates of the vertices of triangle ABC are A(-7, -2), B(-5, -5) and C(-1, -5).

And, the co-ordinates of the vertices of triangle A'B'C' are A'(-4, 4), B'(-2, 1) and C(2, 1).

So, the required translations from the vertices of triangle ABC to A'B'C are

A(-7, -2)   ⇒   A'(-4, 4) = A'(-7+3, -2+6),

B(-5, 5)    ⇒   B'(-2, 1)  = B'(-5+3, -5+6),

C(-1, -5)   ⇒   C'(2, 1)   =  C'(-1+3, -5+6).

So, the required translation rule from triangle ABC to triangle A'B'C' is given by

(x, y)   ⇒   (x+3, y+6).

Now, the co-ordinates of the point H are (1, 3).

So, if the parallelogram EFGH is translated according to the rule (x, y) ⇒ (x+3, y+6), then the co-ordinates of the point H' will be

H(1, 3)  ⇒   H'(1+3, 3+6) = H'(4, 9).

Thus, the required co-ordinates of the point H' are (4, 9).

Option (b) is CORRECT.