Evaluate k^2-4k+3, when k= -2 PLEASER ANSWER ASAP!!!

Mathematics

1 answer:

velikii [3]2 years ago

7 0

Answer:

I hope this helps!

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in the equation 6+3y=4y+2 the variable y represents the same value. Is y= 2,3,4 or 5 the solution of this equation? Explain how

kherson [118]

6 + 3y = 4y +2
3y - 4y = 2 - 6
-y = -4
y = 4

hope that helps :)

3 0

2 years ago

Read 2 more answers

Complete the equation of the line through (-9,-9) and (-6,0)

Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

$(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3$

Thus, the equation is of the form:

$y = 3x + b$

We substitute one of the points and find b:

$0 = 3 (-6) + b\\0 = -18 + b\\b = 18$

Finally, the equation is:

$y = 3x + 18$

Answer:

$y = 3x + 18$

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3 years ago

I Need Help With Statistics

Ilya [14]

Answer: Choice A) mean, there are no outliers

Have a look at the image attached below. I made two dotplots for the data points. The blue points represent bakery A. The red points represent bakery B. For any bakery, the points are fairly close together. There is no point that is off on its own. So there are no outliers, making the mean a good choice for the center. If there were outliers, then the median is a better choice. The mean is greatly affected by outliers, while the median is not.