A sphere of uniform density with mass 21 kg and radius 0.8 m is spinning, making one complete revolution every 0.8 s. the center
1 answer:
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Answer
given,
R = 1-kΩ = 1000 Ω
C = 1-μF
L = 0.2-H
V = V_max sin( ω t)
comparing
V = 150 sin ( 377 t)
ω = 377
Impedance,
Z = 2764.3 Ω
now,
V_{max} = 150 V
Answer:
The maximum traverse acceleration is
Explanation:
Generally the maximum transverse acceleration is mathematically represented as
Where is the angular velocity which is mathematically evaluated as
Substituting the values given in the question
A is the A is amplitude with a value of 2.0mm
Substituting this into the formula for maximum transverse acceleration