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solmaris [256]
3 years ago
11

A car drives to the east in a time of 4 hours. Then, immediately (not realistic, but just assume this is the case for this probl

em), travels 12 km to the west in 4 hours. The average speed for the entire trip is 5 km/hr. What is the average speed of the car for the first part of the trip, in km/hr, while the car was traveling east?
Physics
1 answer:
diamong [38]3 years ago
4 0

Answer:

Average speed in east direction speed=\frac{distance}{time}=\frac{28}{4}=7km/hr            

Explanation:

We have given average speed of the entire trip = 5 km/hr

First the car 4 hours then travels 12 km in 4 hours

So total time of the trip = 4+4 = 8 hours

So total distance traveled in the trip d=speed\times time = 5\times 8=40km

As the car travel 12 km in 4 hours to the west

So distance traveled in 4 hour in east = 40 -12 = 28 km

Time in east direction = 4 hour

So average speed in east direction speed=\frac{distance}{time}=\frac{28}{4}=7km/hr

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Answer:

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a) Given atomic number of an element = 25

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r=4.6656\times 10^{-15} m=4.6656 fm

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) F=k\times \frac{q_1q_2}{a^2}

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q_1=+1.602\times 10^{-19} C

q_2=+1.602\times 10^{-19} C

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a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m

F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}

F=2.6527 N

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

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