A car accelerates from 0 m/s to 20 m/s in 5 seconds,

Assuming things about someone based on your experiences with similar people you have encountered is called

AysviL [449]

Answer:

presumptuous

Explanation:

it's what you call someone who assumes something

3 0

3 years ago

A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th

Elis [28]

Answer:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

$y=y_0+V_0t-gt^2/2$

We are only interested in the vertical motion, so that equation is all what you need.

1. Water ballon is thrown horizontally at sped 2.00 m/s.

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

$y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s$

2. Water ballon thrown straight down at 2.00 m/s

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

$0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s$

To solve the equation you can use the quadratic formula.

$t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92$

You get two times. One of the times is negative, thus it does not have physical meaning.

3. Conclusion:

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0

3 years ago

All the terrestrial planets have

Hoochie [10]

They have solid, rocky surfaces they also have molten heavy-metal core, few moons , and topological features

6 0

3 years ago

You have three identical resistors that you can connect in various ways. Which of the following is NOT a possible value of the e

Snezhnost [94]

Answer: option c.

Explanation: 3 identical resistors can only have 3 configurations

1) all 3 resistors in series

2) all 3 resistors in parallel

3) 2 parallel resistors in series with 1 resistor.

Case 1 : all 3 resistors in series

Let us assume each of the resistor has resistance value R.

The total resistor (Rt) of 3 resistors in series is given as

Rt = R1 + R2 + R3

Since R1=R2=R3=R

Rt = R+R+R = 3R.

Case 2: all 3 resistors in parallel.

The equivalent resistance of resistors in parallel is given by the formulae below.

1/Rt = 1/R1 + 1/R2 + 1/R3

Since R1=R2=R3=R

1/Rt = 1/R + 1/R + 1/R

1/Rt = 1 +1 +1/ R

1/Rt = 3/R

3 * Rt = R

Rt = R/3

Case 3: 2 parallel resistor in series with one

First is to get the equivalent resistance of the 2 parallel resistor.

1/Rt = 1/R1 + 1/R2

But R1=R2=R

1/Rt = 1/R + 1/R

1/Rt = 1 + 1/R

1/Rt = 2/R

2 *Rt = R

Rt =R/2.

R/2 in series with R has an equivalent resistance as shown below

Rt = R/2 + R

Rt = R + 2R/2

Rt = 3R/2

Since all the possible 3 configuration are listed above and there is no other then option c ( 2R/3) is not possible to achieve

4 0

4 years ago

How can u create a fair test?

Vladimir [108]

Answer:

making sure that you change one factor at a time while keeping all other conditions the same

Explanation:

8 0

2 years ago

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