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KatRina [158]
3 years ago
14

What are the two ways to keep us fit and healthy ??​

Physics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

1)Eat healthy food

2)Exercise daily

3)Drink plenty of water

4)Get plenty of sleep

5)Do not take stress

6)Be hygienic

Explanation:

Hope it help Please mark me as brainlest

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Rocks are classified as sedimentary igneous or metamorphic primarily based upon differences in their
yanalaym [24]
The differences in their formations. Igneous is formed by cooled and crystallized rock, sedimentary is formed by sediment compaction and cementation, and metamorphic is formed by intense heat and pressure.
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2 years ago
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One atom has 14 neutrons. Another has 13 neutrons. Both have 13 protons. These atoms are...
agasfer [191]
Hello!

These atoms are isotopes

Isotopes
are atoms with the same number of protons (which determine the atomic number) and a different number of neutrons. These two atoms have the same number of protons (13), but a different number of neutrons, so they are isotopes. 

According to their number of protons, these are Aluminum isotopes: ²⁷Al (stable), and ²⁶Al (radioactive), respectively. 

Have a nice day!

7 0
3 years ago
Investigate the relationship between volume and pressure of a gas at a constant temperature.
sveta [45]
Gay Lussac's Law states: At a constant volume Pressure<span> divided by </span>Temperature<span> is</span>constant<span> P/T = k Together these three laws form the foundation of the Ideal </span>Gas<span>Law. Objective: Students will </span>investigate<span> Gay Lussac's Law relating </span>pressure<span> and</span>temperature<span> at a </span><span>constant temperature.</span>
7 0
3 years ago
When a metal rod is heated, its resistance changes both because of a change in resistivity and because of a change in the length
monitta

Answer:

3.34\Omega

Explanation:

The resistance of a metal rod is given by

R=\frac{\rho L}{A}

where

\rho is the resistivity

L is the length of the rod

A is the cross-sectional area

The resistivity changes with the temperature as:

\rho(T)=\rho_0 (1+\alpha (T-T_0))

where in this case:

\rho_0 is the resistivity of silver at T_0=21.0^{\circ}C

\alpha=6.1\cdot 10^{-3} ^{\circ}C^{-1} is the temperature coefficient for silver

T=180.0^{\circ}C is the current temperature

Substituting,

\rho(180^{\circ}C)=\rho_0 (1+6.1\cdot 10^{-3}(180-21))=1.970\rho_0

The length of the rod changes as

L(T)=L_0 (1+\alpha_L(T-T_0))

where:

L_0 is the initial length at 21.0^{\circ}C

\alpha_L = 18\cdot 10^{-6} ^{\circ}C^{-1} is the coefficient of linear expansion

Substituting,

L(180^{\circ}C)=L_0(1+18\cdot 10^{-6}(180-21))=1.00286L_0

The cross-sectional area of the rod changes as

A(T)=A_0(1+2\alpha_L(T-T_0))

So, substituting,

A(180^{\circ}C)=A_0(1+2\cdot 18\cdot 10^{-6}(180-21))=1.00572A_0

Therefore, if the initial resistance at 21.0°C is

R_0 = \frac{\rho_0 L_0}{A_0}=1.70\Omega

Then the resistance at 180.0°C is:

R(180^{\circ}C)=\frac{\rho(180)L(180)}{A(180)}=\frac{(1.970\rho_0)(1.00285L_0)}{1.00572A_0}=1.9644\frac{\rho_0 L_0}{A_0}=1.9644 R_0=\\=(1.9644)(1.70\Omega)=3.34\Omega

7 0
3 years ago
Which answer is it??
IrinaK [193]

Answer:

hmm...

Explanation:

8 0
3 years ago
Read 2 more answers
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