Ask question

Ask question

All categories

VladimirAG [237]

3 years ago

14

The scores on a math ema tics exam have a mean of 76 and a standard deviation of 7. Find the X-value that corresponds to the Z-s

core 2.942.

1 answer:

Zina [86]3 years ago

3 0

Answer:

ersdf

Step-by-step explanation:

You might be interested in

If I play video-games 5 hours a day, every day, how long would it take to have 1,500 hours of playtime? I would like to know how

Lelu [443]

Answer:

300

Step-by-step explanation:

5÷1500=300

5×3=15

15-15=0

0000

300×5=1500

sorry this the best way I know how to explain

6 0

3 years ago

Read 2 more answers

What is the value of x?

Y_Kistochka [10]

I’m pretty sure the value is 80 because that’s a 90° angle. 90 minus that 10 leaves 80

6 0

3 years ago

Within the set of whole numbers , one set of numbers satisfies the recursive formula an=(an-1)^2-an-1, when a4=870 what are the

andrew11 [14]

Answer: 3 and 6 will be the first and second term of the given series respectively.

Explanation: since it is given- $a_n=(a_{n-1} )^2-a_{n-1}$ and $a_4=870$

so, by replacing n by 4, we will get- $a_4=a_3^2-a_3$ ⇒870= $a_3^2-a_3$ ⇒ $a_3^2-a_3-870=0$

after solving this equation we will get, $a_3= -29$ and 30.

If $a_3= -29$ , but it is not a whole number.

Thus, $a_3=30$ will be the value of third term of the given series.

Again, by applying the given condition $a_n=(a_{n-1} )^2-a_{n-1}$ , $a_2= 6$ or -5 (not possible), so, $a_2=6$ will be the second term.

Similarly, $a_1=3$ or -2 but we will go to the whole number.

Thus, $a_1=3$ will be the first term.

8 0

4 years ago

Read 2 more answers

Solve for 6y+12=3y-3

kherson [118]

6y + 12 = 3y - 3

Subtract 3y on both sides

3y + 12 = -3

Subtract 12 on both sides

3y = -15

Divide by 3 on both sides

y = -5

5 0

4 years ago

Read 2 more answers

Items are inspected for flaws by two quality inspectors. Both inspectors inspect every item and the probability that an item has

Genrish500 [490]

Answer:

a)0.976

b)0.00926

c)0.2402

d)0.35

Step-by-step explanation:

Let $X_i$ be an item passed by inspector i

Let Y be the event that there is a fault in an item

The probability that an item has a flaw is 0.1 i.e. P(Y)=0.1

If a flaw is present ,it will be detected by the first inspector with probability 0.92 i.e. $P(\bar{X_1}|Y)=0.92$

So, $P(X_1|Y)=1-0.92=0.08$

If a flaw is present ,it will be detected by the second inspector with probability 0.7 i.e. $P(\bar{X_2}|Y)=0.7$

So, $P(X_2|Y)=1-0.7=0.3$

If an item does not have a flaw, it will be passed by the first inspector with probability 0.95 i.e. $P(X_1|\bar{Y}) = 0.95$

So, $P(\bar{X_1}|\bar{Y}) = 1-0.95=0.05$

If an item does not have a flaw, it will be passed by the second inspector with probability 0.8 i.e. $P(X_2|\bar{Y}) = 0.8$

So, $P(\bar{X_2}|\bar{Y}) = 1-0.8=0.2$

a)P(found by atleast one inspector | It has flaw )=1-P(found by none inspector | It has flow )

P(found by atleast one inspector | It has flaw )= $1-P(X_1|Y) P(X_2|Y)$

P(found by atleast one inspector | It has flaw )= $1-0.08 \times 0.3$

P(found by atleast one inspector | It has flaw )=0.976

Hence the probability that it will be found by at least one of the two inspectors if it has flaw is 0.976

b) $P(Y|X_1)=\frac{P(X_1|Y) P(Y)}{P(X_1|Y) P(Y)+P(X_1|\bar{Y}) P(\bar{Y})}$

$P(Y|X_1)=\frac{0.08 \times 0.1}{0.08 \times 0.1+0.95 \times 0.9}=0.00926$

C)P( two inspectors draw different conclusions on the same item)= $P(X_1 \cap \bar{X_2} \cap Y)+P(\bar{X_1} \cap X_2 \cap Y)+P(X_1 \cap \bar{X_2} \cap \bar{Y})+P(\bar{X_1} \cap X_2 \cap \bar{Y})$

P( two inspectors draw different conclusions on the same item)=0.2402

D)

$P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2)}\\P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2 \cap Y)+P(X_1 \cap X_2 \cap \bar{Y})}\\P(Y|(X_1 \cap X_2))=0.35$

3 0

3 years ago