the answer is b. energy and matter can enter and leave.
The type of chromosomal mutation that occurs here is an example of a deletion mutation. Specific genetic data, or DNA is removed and the remaining portions of chromosomal information have rejoined.
0:3:1
Explanation:
Tasters have the dominant allele for the itter taste of PTC, they can be homozygous TT and heterozygous Tt.
Non-tasters are supposed as autosomal recessive characters
they are homozygous recessive tt when expressed
Given in the equation two heterozygotes parents would produce offspring with the trait in the following ratio.
Tt (parent 1)
Tt (parent 2)
If a punnet square is made
T t
T TT Tt
t Tt tt
The phenotypic character is in the ratio of 0:3:1
There will be 25% chances of recessive trait of non-tasters in the progeny of heterozygous parents.
Complete question:
Molecule 1 has the nitrogenous base sequence TCA AGT. Which set of bases in Molecule 2 can bond to that sequence in a complementary way?
a. UCAAGU
B. AGTACA
C. AGUUCA
D. UCAATA
Answer:
C. AGUUCA
Explanation:
DNA template strand and the corresponding RNA have complementary sequences. Adenine in the DNA template strand pairs with "uracil" base of RNA while cytosine pairs with its "guanine" base. Similarly, thymine base in DNA template strand pairs with "adenine" base in the RNA. This occurs since RNA does not have a thymine base. RNA has uracil base instead. Therefore, the molecule 1 with sequence TCA AGT would bind to the molecule 2 with the " AGU UCA" sequence.
Molecule 1: DNA template: TCA AGT
Molecule 2: mRNA: AGUUCA
Answer:
DNA is converted into RNA
Explanation:
hope i helped you
